The solution to the equation x(x+4) = 6 is x = -2 + √10 or x = -2 - √10 after solving with the quadratic formula.
<h3>What is a quadratic equation?</h3>
Any equation of the form 
where x is variable and a, b, and c are any real numbers where a ≠ 0 is called a quadratic equation.
As we know, the formula for the roots of the quadratic equation is given by:
We have an equation:
x(x + 4) = 6
By distributive property:
x² + 4x = 6
x² + 4x - 6 = 0
a = 1, b = 4, c = -6
Plugging all the values in the formula:
After calculating:
Thus, the solution to the equation x(x+4) = 6 is x = -2 + √10 or x = -2 - √10 after solving with the quadratic formula.
Learn more about quadratic equations here:
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Answer:
x=7, -2.
Step-by-step explanation:
x^2-5x=14
x^2-5x-14=0
factor out the trinomial,
(x-7)(x+2)=0
zero property,
x-7=0, x+2=0,
x=0+7=7,
x=0-2=-2
M= 20 because the rate of change is -3.
The domain is the set of x-values of a function. The range is the set of y-values of a function.
You are told that the domain, or x-values, are -8, -6, -3, -2, and 2. To find the range, you just need to plug in each of the x-values into the function <span>y = -3x + 7 and find the value of y.
1) When x = -8:
</span><span>y = -3x + 7
y = -3(-8) + 7
y = 24 + 7
y = 31
2) When x = -6
</span>y = -3x + 7
y = -3(-6) + 7
y = 18 + 7
y = 25
3) When x = -3
y = -3x + 7
y = -3(-3) + 7
y = 9 + 7
y = 16
4) When x = -2
y = -3x + 7
y = -3(-2) + 7
y = 6 + 7
y = 13
5) When y = 2
y = -3x + 7
y = -3(2) + 7
y = -6 + 7
y = 1
The range is {31, 25, 16, 13, 1}.
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Answer: {31, 25, 16, 13, 1}
Answer:
Here are my answers
hope this helps
Step-by-step explanation:
1. isosceles triangle
2. 3x + 15 = 90 x = 25
x + 25 = 90 x = 65
x + 55 = 90 x = 35
3. The size for DAB is 84
My reasoning is I went from one angle to another by subtracting 180 from my answers. For example angle 132 is supplementary to the missing angle next to it. I subtract 180 from 132 and get 48. That already solves the 2 equivalent angles in the triangle so I have 48+48+x = 180 because a full triangle equals 180. I get x = 84 then I do the same thing I did with angle 132. Angle 84 is supplementary to the missing angle next to it. I subtract 84 from 180 and get 96 then go diagonal from angle C (which is 96) to angle A. Those are supplementary so I subtract 96 from 180 and get 84.
