To find this you would just subtract 28 - 3 = 5. So now you subtract 28 - 5 = 23.
- 23-5= 18 etc. so on and so forth. Your numbers would be 28, 23, 18, 13, 8, 3.
Answer: About 800 thousand
The more accurate value is 807,528 but this is also an approximation.
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Work Shown:
![t = \text{number of years since the year 2000}](https://tex.z-dn.net/?f=t%20%3D%20%5Ctext%7Bnumber%20of%20years%20since%20the%20year%202000%7D)
![P_0 = \text{population (in millions) in the year 2000}](https://tex.z-dn.net/?f=P_0%20%3D%20%5Ctext%7Bpopulation%20%28in%20millions%29%20in%20the%20year%202000%7D)
![P = P_0(1.2)^t\\\\5 = P_0(1.2)^{10}\\\\5 \approx P_0*6.1917364224\\\\P_0 \approx \frac{5}{6.1917364224}\\\\P_0 \approx 0.80752791444922\\\\P_0 \approx 0.807528\\\\](https://tex.z-dn.net/?f=P%20%3D%20P_0%281.2%29%5Et%5C%5C%5C%5C5%20%3D%20P_0%281.2%29%5E%7B10%7D%5C%5C%5C%5C5%20%5Capprox%20P_0%2A6.1917364224%5C%5C%5C%5CP_0%20%5Capprox%20%5Cfrac%7B5%7D%7B6.1917364224%7D%5C%5C%5C%5CP_0%20%5Capprox%200.80752791444922%5C%5C%5C%5CP_0%20%5Capprox%200.807528%5C%5C%5C%5C)
That's the rough population of wild pigs (in millions) for the year 2000.
Multiply by
to get it in terms of units instead.
![0.807528\times10^6 = 807,528](https://tex.z-dn.net/?f=0.807528%5Ctimes10%5E6%20%3D%20807%2C528)
There were roughly 800 thousand wild pigs in the year 2000.
Answer:
the answer to your question is 3
Step-by-step explanation:
2 and 5/8 is 2.625 rounding gives you 3
Answer:
37%
Step-by-step explanation:
First to find the percent of decrease you have subtract the largest number by the smaller number. So 78 ft² - 49.14 ft². This would get you to 28.86 ft². Then you would divide the original number, (in this case 78) by the difference (28.86). Once you divide you get .37, you will have to multiply by 100 to get the percent. So the percent of decrease is 37%.