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Scilla [17]
3 years ago
7

Heather has a bag with 9 marbles, 9 tennis balls, 10 apples, and 2 books. What is the ratio of books to tennis balls?

Mathematics
1 answer:
sveticcg [70]3 years ago
3 0

Answer:

Option A, (2/9) or 2:9

Step-by-step explanation:

<u>Amount of books:</u>  2 books

<u>Amount of tennis balls:</u>  9 tennis balls

Books : Tennis Balls

<em>2 : 9</em>

<em />

Answer:  Option A, (2/9) or 2:9

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You have a puppy named Fido and 60 feet of fencing. You want to make him the largest play area possible. What are the dimensions
LUCKY_DIMON [66]

Answer:

<u>15 feet x 15 feet</u>

Step-by-step explanation:

I'm worried about Fido, so I'll use three different approaches to maximizing his play space:  Graphing, Chart, and First Derivative.  This is perhaps more than Fido wants, but it hopefully offers ideas on how these types of problems can be answered.

=========================

Fido is limited to 60 feet of fence, which will form the perimeter.  The area  of a rectangle is (length)*(width).  Let's set length to L and width to W.  I'll use A for area.

Therefore A = L*W

The rectangle's perimeter will be 2L + 2W, and this is equal to 60 feet:

2L + 2W = 60

Let's rearrange this equation to isolate either W or L.  I chose L:

L + W = 30

L = 30 - W

Now let's use this definition of L in the Area equation:

A = L*W

A = (30-W)*W

A = 30W - W^2

<u>Graphing</u>

We can graph this function (A = 30W - W^2) to find the maximum area.  See the attached image.  We find a maximum area of 225 ft^2 when the width is 15 feet.  15 feet would mean that Fido's roaming pen will be in the shape of a square;  15 feet for each side equals 60 feet total fence.

<u>Chart</u>

One can also find a maximum by calculating a variety of conditions set by L = 30 - W.  I randomly picked lengths from 2 to 24 feet and calculated the resulting width and then the resultant area for each condition.  See attached image.  Although I did not pick 15 feet, we can see that the area increases until the length transitions from 14 to 16 feet.  It reverses direction at that point. A closer inspection around those values will show that 15 feet is, in fact, the optimum value to produce a pen with the most area.

<u>First Derivative</u>

One could also take the first derivative of the equation A = 30W - W^2 and set it equal to zero.  The fist derivative tells us the slope of the line at any point (for a value of W in this example).  The slope is zero only when the curve hits a maximum.

A = 30W - W^2

A' = 30 -2W

0 = 30 - 2W

2W = 30

W = 15 feet

The slope is zero when the width is 15 feet.  15 feet is the optimum for creating a pen with the most area possible with 60 feet of fence.

===

All three approaches yield the same result.  Graphing is fun when you have access to DESMOS.  Charts are fun if you like Excel.  Derivatives can also be fun, mostly because I always ponder "Who had the audacity to think this might work?"  (Didn't they have something more important to do?  Raid a village, etc.?).

====

Arf

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14/34 is simplified to 7/17
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Vesnalui [34]

Answer:

is that the number in the middle = then more the -3 to 2x add in you get 1 being y=1 so 1 -3 is 2x

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Answer:

its the letter 6

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i took the test

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N-31 divided by 4 equals 2
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Answer:

39-31=8

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2 years ago
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