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3 years ago

jalen found an outfit that is 20% off of the original price of $65. Find the discounted price of the outfit.

Mathematics

1 answer:

olga55 [171]3 years ago

7 0

Answer:

$52

Step-by-step explanation:

0.2 x 65 = 13

65-13 = 52

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PLEASE HELP I AM STUCK ON THIS TOO!!!

Kryger [21]

R=0.957, because 68 ->70

3 0

3 years ago

The cost of 4 cartons of fresh cream is 5.76. What is the cost of 13 such Cartons?

TiliK225 [7]

Answer:

18.72

Step-by-step explanation:

cost of four cartons = $ 5.76

cost of one carton = $ 5.76/4

cost of 13 cartons= $ 5.76/4× 13

=$ 18.72

7 0

3 years ago

Read 2 more answers

The co-ordinates of the point where the line y=x+4 crosses the y-axis

OverLord2011 [107]

Answer:

Therefore the required point where it crosses y-axis is (0 , 4)

Step-by-step explanation:

Given:

$y=x+4$ ...............Equation of line

Intercepts:

The line which intersect on x-axis and y-axis are called intercepts.

There are two intercepts:

x-intercept: The line which intersect at x-axis. So when the line intersect at x-axis Y coordinate is zero.

y-intercept: The line which intersect at y-axis. So when the line intersect at y-axis X coordinate is zero.

For a line crosses Y-axis we have,

$y=x+4$

Put x = 0 in above equation we get

$y=0+4=4\\y=4$

Therefore the required point where it crosses y-axis is (0 , 4)

4 0

3 years ago

Find a potential function for the vector field

alexdok [17]

(a) We want to find a scalar function $f(x,y,z)$ such that $\mathbf F = \nabla f$ . This means

$\dfrac{\partial f}{\partial x} = 2xy + 24$

$\dfrac{\partial f}{\partial y} = x^2 + 16$

Looking at the first equation, integrating both sides with respect to $x$ gives

$f(x,y) = x^2y + 24x + g(y)$

Differentiating both sides of this with respect to $y$ gives

$\dfrac{\partial f}{\partial y} = x^2 + 16 = x^2 + \dfrac{dg}{dy} \implies \dfrac{dg}{dy} = 16 \implies g(y) = 16y + C$

Then the potential function is

$f(x,y) = \boxed{x^2y + 24x + 16y + C}$

(b) By the FTCoLI, we have

$\displaystyle \int_{(1,1)}^{(-1,2)} \mathbf F \cdot d\mathbf r = f(-1,2) - f(1,1) = 10-41 = \boxed{-31}$

$\displaystyle \int_{(-1,2)}^{(0,4)} \mathbf F \cdot d\mathbf r = f(0,4) - f(-1,2) = 64 - 41 = \boxed{23}$

$\displaystyle \int_{(0,4)}^{(2,3)} \mathbf F \cdot d\mathbf r = f(2,3) - f(0,4) = 108 - 64 = \boxed{44}$

7 0

2 years ago

Graph the solution for the following inequality : -y <img src="https://tex.z-dn.net/?f=%5Cleq" id="TexFormula1" title="\leq" alt

Aleonysh [2.5K]

First I would isolate the "y"/make the "y" positive.

-y ≤ 4x

Divide -1 on both sides (if you multiply or divide by a negative number/variable, you flip the sign [< , > , ≤ , ≥])

y ≥ -4x

You can think of this inequality like the slope intercept form: y=mx + b

"m" is the slope, "b" is the y-intercept(when x = 0). The only difference is that the sign is not an equal sign. The slope is -4, and since you don't have a y-intercept, you start from the origin. So your line is decreasing.

When the sign is ≤ or ≥ ("less/greater than <u>or equal to</u>"), the line is a solid line.

When the sign is < or >, the line is a dotted line.

Based on the inequality, the "y" is <u>greater than or equal to</u> the equation(-4x), so the shaded area is above the line, and the line is solid.

Your answer is A

4 0

4 years ago