Answer:
![7\frac{3}{8} \ miles](https://tex.z-dn.net/?f=7%5Cfrac%7B3%7D%7B8%7D%20%5C%20miles)
Step-by-step explanation:
Given:
After lunch the friends walked 6 3/4 miles before arriving at the end of the trail.
The trail is 14 1/8 miles long.
Question asked:
How long did the friends walk before lunch ?
Solution:
Let the friends walk before lunch in miles = ![x](https://tex.z-dn.net/?f=x)
As total length of trail is given
, we can conclude:
Total length of trail = The friends walk before lunch in miles + The friends walk after lunch in miles
![14\frac{1}{8} =x+6\frac{3}{4} \\ \frac{14\times8+1}{8}=x+\frac{6\times4+3}{4} \\\frac{113}{8} =x+\frac{27}{4}](https://tex.z-dn.net/?f=14%5Cfrac%7B1%7D%7B8%7D%20%3Dx%2B6%5Cfrac%7B3%7D%7B4%7D%20%5C%5C%20%5Cfrac%7B14%5Ctimes8%2B1%7D%7B8%7D%3Dx%2B%5Cfrac%7B6%5Ctimes4%2B3%7D%7B4%7D%20%5C%5C%5Cfrac%7B113%7D%7B8%7D%20%3Dx%2B%5Cfrac%7B27%7D%7B4%7D)
Subtracting both side by ![\frac{27}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B27%7D%7B4%7D)
![\frac{113}{8} -\frac{27}{4} =x+\frac{27}{4}-\frac{27}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B113%7D%7B8%7D%20-%5Cfrac%7B27%7D%7B4%7D%20%3Dx%2B%5Cfrac%7B27%7D%7B4%7D-%5Cfrac%7B27%7D%7B4%7D)
Taking LCM of 4 and 8 ,we get 8
![\frac{113-54}{8} =x\\\\\frac{59}{8} =x\\\ \\7\frac{3}{8} = x](https://tex.z-dn.net/?f=%5Cfrac%7B113-54%7D%7B8%7D%20%3Dx%5C%5C%5C%5C%5Cfrac%7B59%7D%7B8%7D%20%20%3Dx%5C%5C%5C%20%5C%5C7%5Cfrac%7B3%7D%7B8%7D%20%3D%20x)
Therefore, the friends walk before lunch is
.
Answer:
x= 33
Step-by-step explanation:
Answer:In geometry, the parallel postulate, also called Euclid's fifth postulate because it is the fifth postulate in Euclid's Elements, is a distinctive axiom in Euclidean geometry. It states that, in two-dimensional geometry
Answer:
24feet 1 inches
Step-by-step explanation:
Answer:
30.00
Step-by-step explanation:
Hope this helps!