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Paladinen [302]
2 years ago
12

A person throws a ball and it unfortunately gets stuck on top of a building. The building is 64.2 feet tall, and he will have to

place a ladder on the ground at an angle of 46 degrees to reach the top of the building. How long does the ladder need to be to reach the top of the building?
Mathematics
1 answer:
yawa3891 [41]2 years ago
8 0

Answer: To add to the confusion, a lot of ladders aren't labeled properly. When recently shopping, I discovered that the advertised height on the ladders I was looking at was about 20% less than the actual practical height of the ladder. Beware the small print!

Also, no matter how safe you are, note that 24' is a LOT higher from above than below. :) I recently cleaned the gutters on the 3 storey side of my house. Never again.

Step-by-step explanation:Why would you BUY a ladder you will use but once? Go rent, even contractors rent ladders. The rental companies make sure their equipment is safe. They will advise you because your success means less insurance costs. I have a problem with a homeowner climbing this high, not experienced and without protection/harnesses. You need to rent a fire truck? They also rent boom trucks but one has to prove competence. Whatever you are trying to DIY there are limits and this is definitely one I would have insisted you get a professional. I doubt that your home owner's would cover a fall.

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All of the following are equivalent except<br> 7x2<br> 4x+3x<br> (4+3)x<br> 7x
swat32

Answer:

7x2

Step-by-step explanation:

7x2 is 14 and all the other ones equal 7

6 0
3 years ago
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Find an equation in standard form for the hyperbola with vertices at (0, ±3) and foci at (0, ±7)
Nitella [24]

The equation of a hyperbola is:

(x – h)^2 / a^2 - (y – k)^2 / b^2 = 1

 

So what we have to do is to look for the values of the variables:

<span>For the given hyperbola : center (h, k) = (0, 0)
a = 3(distance from center to vertices)
a^2 = 9</span>

<span>
c = 7 (distance from center to vertices; given from the foci)
c^2 = 49</span>

 

<span>By the hypotenuse formula:
c^2 = a^2 + b^2
b^2 = c^2 - a^2 </span>

<span>b^2 =  49 – 9</span>

<span>b^2  = 40

</span>

Therefore the equation of the hyperbola is:

<span>(x^2 / 9) – (y^2 / 40) = 1</span>

5 0
3 years ago
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Circle A has been enlarged to create circleA prime . The picture below shows the diameters of both circles.
igomit [66]

Answer:

Step-by-step explanation:

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2 years ago
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Simplify the picture below
podryga [215]
((x^2-3x-18)/(x+3))
((x-6)(x+3))/(x+3)
The x+3 on top cancels out the x+3 on the bottom so all you have left is

x-6


Hope I didn't mess up for your sake!
3 0
3 years ago
Y=–6x+2<br> –12x – 2y=–4<br> How many solutions does this linear system have?
DerKrebs [107]

The linear equation y = -6x + 2; -12x - 2y = -4 has no solution

<h3>Linear equation</h3>

y = -6x + 2

-12x - 2y = -4

  • Substitute y = -6x + 2 into (2)

-12x - 2y = -4

-12x - 2(-6x + 2) = -4

-12x + 12x -4 = -4

-12x + 12x = - 4 + 4

0 = 0

  • Solve for x

y = -6x + 2

y - 2 = -6x

x = (y - 2) / -6

  • Substitute into (2)

-12x - 2y = -4

-12(y- 2)/ 6 - 2y = -4

(-12y + 24) / 6 - 2y = -4

-2y + 4 - 2y = 4

0 = 0

Learn more about linear equation:

brainly.com/question/4074386

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3 0
2 years ago
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