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3 years ago

9

Which graph shows a function whose inverse is also a function?

2 answers:

lesya692 [45]3 years ago

8 0

Answer:

A -- the curves that are not parabolas

Step-by-step explanation:

The inverse relation will only be a function if it passes the vertical line test: a vertical line cannot intersect the curve at more than one point.

A "half-parabola" can have an inverse function.

A parabola will have an inverse relation that is not a function. When x-values are repeated, as "goes through (5, 2) and goes through (5, -2)", the relation is not a function.

The graph that shows inverse functions is attached. A function and its inverse are mirror images of each other in the line y=x.

BartSMP [9]3 years ago

6 0

Answer:

A

Step-by-step explanation:

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5y^2+5−4−4y^2+5y^2−4x^3 −1

vredina [299]

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{4 {x}^{3} + 6 {y}^{2} }}}}}$

Step-by-step explanation:

$\sf{5 {y }^{2} + 5 - 4 - 4 {y}^{2} + 5 {y}^{2} - 4 {x}^{3} - 1}$

Collect like terms

⇒ $\sf{ 4 {x}^{3} + 5 {y}^{2} - 4 {y}^{2} + 5 {y}^{2} + 5 - 4 - 1}$

⇒ $\sf{4 {x}^{3} + {y}^{2} + 5 {y}^{2} + 5 - 4 - 1}$

⇒ $\sf{4 {x}^{3} + 6 {y}^{2} + 5 - 4 - 1}$

Calculate

⇒ $\sf{4 {x}^{3} + 6 {y}^{2} + 1 - 1}$

⇒ $\sf{4 {x}^{3} + 6 {y}^{2} }$

Hope I helped!

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6 0

2 years ago

Find the GCF of n 3 t 2 and nt 4.

borishaifa [10]

The GCF is 1

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7 0

3 years ago

Read 2 more answers

17x-3y=4 2x-4y=1 the solution to the system of equations is

Burka [1]

ANSWER

$x=\frac{13}{62}$

and

$y= \frac{-9}{62}$ e have

EXPLANATION

$17x-3y=4---(1)$

$2x-4y=1$

Let us make y the subject and call it equation (2)

$2x=1+4y$

$x=\frac{1}{2}+2y--(2)$

We put equation (2) in to equation (1)

$17(\frac{1}{2}+2y)-3y=4$

$\frac{17}{2}+34y-3y=4$

$34y-3y=4- \frac{17}{2}$

Simplify to get,

$31y= \frac{8-17}{2}$

$31y= \frac{-9}{2}$

Divide both sides by 31,

$y= \frac{-9}{2} \div 31$

$y= \frac{-9}{2} \times \frac{1}{31}$

$y= \frac{-9}{62}$

We put this value in to equation (2) to get,

$x=\frac{1}{2}+2\times -\frac{9}{62}$

$x=\frac{1}{2} -\frac{18}{62}$

We collect LCM to obtain,

$x=\frac{31-18}{62}$

$x=\frac{13}{62}$

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2 years ago

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2 years ago

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alekssr [168]

Answer:

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Step-by-step explanation:

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2 years ago

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