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Shtirlitz [24]
3 years ago
11

Which transformations are needed to change the parent sine function to

Mathematics
2 answers:
LenKa [72]3 years ago
8 0

Answer:

B

Step-by-step explanation:

The parent sine function is given by y=sin(x). For this function we have the following data

Period:2\pi

Phase Shift: 0 for Phase Shift is given by y=sen(x-k)=senx Then sin(x-0)=sinx

-k=0

When we transform this function, dilating it, we multiply the function by 1/4 or divide by 4, so we compress it. And Increase the phase shift by adding values to the x, like it was done in

y= 1/4 sin[4(x+pi/6)]

Period: \frac{\pi}{2}

Phase shift: - (\pi/6) For y=1/4 sin[4(x+pi/6)] as the sign of +\frac{\pi}{6} the phase shift is actually -\frac{\pi}{6} units, or \frac{\pi}{6} to the left.

vesna_86 [32]3 years ago
3 0
A. Vertical stretch of 1/4 hortionzal stretch to a period of 2pi , phase shift of pi/6 units to the left
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Witch statement best describes how to determine whether f(x) =x^3+5x+1 is an even function?
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A.Determine whether –(x3 + 5x + 1) is equivalent to x3 + 5x + 1. b.Determine whether (–x)3 + 5(–x) + 1 is equivalent to x3 + 5x + 1.
c. Determine whether –x3 + 5x + 1 is equivalent to –(x3 + 5x + 1).
d. Determine whether (–x)3 + 5(–x) + 1 is equivalent to –(x3 + 5x + 1)

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b.Determine whether (–x)3 + 5(–x) + 1 is equivalent to x3 + 5x + 1. 
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Which statements are true for the functions g(x) = x^2 and h(x)= -x^2? Check all that apply.
kogti [31]

Answer:

A, C, E & F are true

Step-by-step explanation:

We are given the functions;

g(x) = x² and h(x)= -x²

Let's analyze the options;

A) For any value of x,g(x) will always be greater than h(x);

Let's put x = 1 in both functions;

g(x) = 1² = 1

h(x) = - (1)² = - 1

Let's try a negative number say -1:

g(x) = (-1)² = 1

h(x) = -(-1)² = -1

In both cases, we see that g(x) > h(x) and so the statement is true.

B) For any value of x,h(x) will always be greater than g(x); As seen in A above, for any value of x, h(x) will always be greater than g(x). And so this statement here is wrong.

C) g(x) > h(x) for x = -1;

As seen in A above, at x = -1, g(x) > h(x).

Thus, this statement is true

D) g(x) < h(x) for x = 3;

g(x) = (3)² = 9

h(x) = -(3)² = -9

g(x) is not less than h(x) and so the statement is not correct.

E) For positive values of x, g(x) > h(x).

We have tried positive numbers at x = 1 and x = 3 in previous answers above and in both cases, g(x) > h(x).

Thus, statement is true.

F) For negative values of x, g(x) > h(x).

We have seen earlier that at a negative value of x = -1, g(x) > h(x)

Let's try x = -2

g(x) = (-2)² = 4

h(x) = -(-2)² = -4

Still seeing that g(x) > h(x).

Thus the statement is true.

6 0
3 years ago
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