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sergij07 [2.7K]
3 years ago
5

Help please Show two different ways to factor -2x - 10

Mathematics
1 answer:
Arada [10]3 years ago
3 0
-2(x+5) OR 2(-x-5) I hope that helps if not please let me know!
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Write a word problem that can be described by the division expression 3÷1/4. Use complete sentences in your answer
AURORKA [14]
The question is simply asking us to create a word problem.
The word problem describing the division expression  3÷1/4 will be:
Given that Annie has 3 oranges and he wants to each orange into quarters, how many quarters will Annie have in total?
 
4 0
3 years ago
Read 2 more answers
Ronnie collects horseshoes and hand grenades and places
lesantik [10]

Answer: 3.5 pounds

Step-by-step explanation:

3 s   + 7 h = 32        s = shoes   h= hand grenades

6 s   + 2 h = 22        Multiply first equation by -2   and add to second equation to get :

-12 h = -42

h = 3.5 pounds

sorry if this was late

8 0
2 years ago
find the spectral radius of A. Is this a convergent matrix? Justify your answer. Find the limit x=lim x^(k) of vector iteration
Natasha_Volkova [10]

Answer:

The solution to this question can be defined as follows:

Step-by-step explanation:

Please find the complete question in the attached file.

A = \left[\begin{array}{ccc} \frac{3}{4}& \frac{1}{4}& \frac{1}{2}\\ 0 & \frac{1}{2}& 0\\ -\frac{1}{4}& -\frac{1}{4} & 0\end{array}\right]

now for given values:

\left[\begin{array}{ccc} \frac{3}{4} - \lambda & \frac{1}{4}& \frac{1}{2}\\ 0 & \frac{1}{2} - \lambda & 0\\ -\frac{1}{4}& -\frac{1}{4} & 0 -\lambda \end{array}\right]=0 \\\\

\to  (\frac{3}{4} - \lambda ) [-\lambda (\frac{1}{2} - \lambda ) -0] - 0 - \frac{1}{4}[0- \frac{1}{2} (\frac{1}{2} - \lambda )] =0 \\\\\to  (\frac{3}{4} - \lambda ) [(\frac{\lambda}{2} + \lambda^2 )] - \frac{1}{4}[\frac{\lambda}{2} -  \frac{1}{4}] =0 \\\\\to  (\frac{3}{8}\lambda + \frac{3}{4} \lambda^2 - \frac{\lambda^2}{2} - \lambda^3 - \frac{\lambda}{8} + \frac{1}{16}=0 \\\\\to (\lambda - \frac{1}{2}) (\lambda -\frac{1}{4}) (\lambda - \frac{1}{2}) =0\\\\

\to \lambda_1=\lambda_2 =\frac{1}{2}\\\\\to \lambda_3 = \frac{1}{4} \\\\\to A = max {|\lambda_1| , |\lambda_2|, |\lambda_3|}\\\\

       = max{\frac{1}{2}, \frac{1}{2}, \frac{1}{4}}\\\\= \frac{1}{2}\\\\(A) =\frac{1}{2}

In point b:

Its  

spectral radius is less than 1 hence matrix is convergent.

In point c:

\to c^{(k+1)} = A x^{k}+C \\\\\to x(0) =   \left(\begin{array}{c}3&1&2\end{array}\right)  , c = \left(\begin{array}{c}2&2&4\end{array}\right)\\\\  \to x^{(k+1)} =  \left[\begin{array}{ccc} \frac{3}{4}& \frac{1}{4}& \frac{1}{2}\\ 0 & \frac{1}{2}& 0\\ -\frac{1}{4}& -\frac{1}{4} & 0\end{array}\right] x^k + \left[\begin{array}{c}2&2&4\end{array}\right]  \\\\

after solving the value the answer is

:

\lim_{k \to \infty} x^k=o  = \left[\begin{array}{c}0&0&0\end{array}\right]

4 0
3 years ago
Simply the expression-2.3(4r+5)-3.6r
laiz [17]

Answer:

Step-by-step explanation:

you need to cancel out the brackets by multiplying -2.3 with every thing inside the brackets

3 0
3 years ago
Read 2 more answers
Please please help !!!!!!!!
adoni [48]

Answer:

98°

142°

83°

97°

Step-by-step explanation:

m(arc)JL = 2 × 49° = 98°

m(arc)MJ = 360° - 120° - 98° = 142°

m<KJM = (120° + 46°)/2 = 83°

m<KLM = (360° - 120° - 46°)/2 = 97°

8 0
2 years ago
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