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maria [59]
3 years ago
8

Last year, the city library collected 117 used books for its shelves.This year, it collected 3 times as many books. How many boo

ks did it collect this year?
Mathematics
1 answer:
andrezito [222]3 years ago
5 0
They collected 351 books this year

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Solve for x.<br> –4.5(x – 8.9) = 12.6<br> OVEC<br> Enter your answer, as a decimal, in the box.
Gnoma [55]

Step-by-step explanation:

just take -4.5 the right side

3 0
3 years ago
PLEASE HELP WILL CROWNNNNNN!!!!!
Serga [27]

Answer:

12

7

2

- 3

- 8

Step-by-step explanation:

f ( - 2 )

= 2 - 5 ( - 2 )

= 2 - ( - 10 )

= 2 + 10

= 12

f ( - 1 )

= 2 - 5 ( - 1 )

= 2 - ( - 5 )

= 2 + 5

= 7

f ( 0 )

= 2 - 5 ( 0 )

= 2

f ( 1 )

= 2 - 5 ( 1 )

= 2 - 5

= - 5 + 2

= - 3

f ( 2 )

= 2 - 5 ( 2 )

= 2 - 10

= - 10 + 2

= - 8

6 0
3 years ago
A manufacturer knows that their items have a normally distributed length, with a mean of 15.4 inches, and standard deviation of
Masteriza [31]

Answer:

0.9452 = 94.52% probability that their mean length is less than 16.8 inches.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 15.4 inches, and standard deviation of 3.5 inches.

This means that \mu = 15.4, \sigma = 3.5

16 items are chosen at random

This means that n = 16, s = \frac{3.5}{\sqrt{16}} = 0.875

What is the probability that their mean length is less than 16.8 inches?

This is the p-value of Z when X = 16.8. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{16.8 - 15.4}{0.875}

Z = 1.6

Z = 1.6 has a p-value of 0.9452.

0.9452 = 94.52% probability that their mean length is less than 16.8 inches.

5 0
3 years ago
A pizza shop sells three sizes of pizza, and they track how often each size gets ordered along with how much they profit from ea
777dan777 [17]

Answer:

The mean and standard deviation of Y is $6.56 and $2.77 respectively.

Step-by-step explanation:

Consider the provided information.

Let Y represent their profit on a randomly selected pizza with this promotion.

The company is going to run a promotion where customers get $2 off any size pizza.

Therefore, Y=\text{Profit}-\$2

Y=X-\$2

So the mean will be reduced by 2.

\mu_Y=\mu_X-\$2

\mu_Y =\$ 8.56 - \$2

\mu_Y =\$6.56

If we add or subtract any constant number from a given distribution, then the mean is changed by the same number(i.e constant number) but the standard deviation will remain the same.

Therefore \sigma_Y=\sigma_X=2.77

Hence, the mean and standard deviation of Y is $6.56 and $2.77 respectively.

3 0
3 years ago
If I can walk 9673.6 meters in 5 hours. How far can I walk in 70 minutes. ( I need the work)
den301095 [7]

First, convert 5 hours into minutes:

5 hours 60 min

------------ * --------------- = 300 min

1 1 hr

Next, find the unit rate in m/min:

9673.6 m

--------------- = 32.24 m/min

300 min

Now find the distance you can walk in 70 minutes at this rate:

32.24 m

------------- * 70 min = 2247 meters (answer)

1 min

You could walk 2247 meters (to the nearest meter) in 70 minutes.

6 0
3 years ago
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