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zhuklara [117]
3 years ago
5

What is the domain of h?

Mathematics
1 answer:
Alexandra [31]3 years ago
8 0

Answer:

{-2, -1, 1, 5, 6}

Step-by-step explanation:

The domain includes the five x-values (inputs):  {-2, -1, 1, 5, 6}

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NEED HELP! will give brainiest!!
Flura [38]

Answer: 62999

Step-by-step explanation: sorry if wrong

3 0
2 years ago
PLS HELP ILL GIVE BRAINLIST!
RideAnS [48]

Answer:

The length of AP will be 14 units.

Step-by-step explanation:

As P is the centroid of ΔABC as shown in question figure.

As the side AB of the triangle has the midpoint D, the side AC of the triangle has the midpoint F and the side BC of the triangle has the

midpoint E.

Hence, CD, BF and AE being medians of ΔABC.

The point of intersection of these medians will be the centroid of the triangle. Hence, P is the centroid of ΔABC

According to rule, the centroid point of the triangle ΔABC divides each median into two segments in the ratio 2 : 1.

So,

AP = \frac{2}{3} AE

As the value of AE = 21

So,

AP = \frac{2}{3} (21)

AP = 14

So, the length of AP will be 14 units.

Keywords: centroid, triangle

Learn more about the centroid of triangle from brainly.com/question/7722758

#learnwithBrainly

5 0
3 years ago
Can i have some help (marked an Brainllest)
Marysya12 [62]
can you send me the answer
3 0
3 years ago
A supplier delivers an order for 20 electric toothbrushes to a store. By accident, three of the electric toothbrushes are defect
krek1111 [17]

Answer:

The probability that the first two electric toothbrushes sold are defective is 0.016.

Step-by-step explanation:

The probability of an event, say <em>E </em>occurring is:

P (E)=\frac{n(E)}{N}

Here,

n (E) = favorable outcomes

N = total number of outcomes

Let <em>X</em> = number of defective electric toothbrushes sold.

The number of electric toothbrushes that were delivered to a store is, <em>n</em> = 20.

Number of defective electric toothbrushes is, <em>x</em> = 3.

The number of ways to select two toothbrushes to sell from the 20 toothbrushes is:

{20\choose 2}=\frac{20!}{2!(20-2)!}=\frac{20!}{2!\times 18!}=\frac{20\times 19\times 18!}{2!\times 18!}=190

The number of ways to select two defective toothbrushes to sell from the 3 defective toothbrushes is:

{3\choose 2}=\frac{3!}{2!(3-2)!}=\frac{3!}{2!\times 1!}=3

Compute the probability that the first two electric toothbrushes sold are defective as follows:

P (Selling 2 defective toothbrushes) = Favorable outcomes ÷ Total no. of outcomes

                                                            =\frac{3}{190}\\

                                                            =0.01579\\\approx0.016

Thus, the probability that the first two electric toothbrushes sold are defective is 0.016.

8 0
3 years ago
I need helpppppppppppppppppp
notsponge [240]

Answer:

A:

9×1=9

9×2=18

9×3=27

9×4=36

9×5=45

9×6=54

9×7=63

9×8=72

9×9=81

9×10=90

B:

It goes down by 1 after multiplying a bigger number.

C:

It goes up by 1 after multiplying a bigger number.

Step-by-step explanation:

hope this helps you and have a great day

4 0
3 years ago
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