Let R be a set of nine distinct integers. Six of the elements of the set are 2, 3, 4, 6, 9, and 14. Find the number of possible
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9514 1404 393
Answer:
(x +6)^2 +(y -10)^2 = 225
Step-by-step explanation:
The standard form equation for a circle is ...
(x -h)^2 + (y -k)^2 = r^2
where the center is (h, k) and the radius is r.
The center of a circle is the midpoint of any diameter. The midpoint between two points is the average of their coordinates.
((-15, -2) +(3, 22))/2 = (-15+3, -2+22)/2 = (-6, 10)
The radius can be found using the distance formula, or by simply putting one of the given points in the equation for the circle to see what the constant (r^2) needs to be.
(x -(-6))^2 +(y -10)^2 = (-15-(-6))^2 +(-2-10)^2
(x +6)^2 +(y -10)^2 = 81 +144 = 225
The equation of the circle is ...
(x +6)^2 +(y -10)^2 = 225
Given number is 78/14.
We have to find two whole numbers between which given number 78/14 lies.
Let's convert that into mixed fraction.
To do that we divide 78 by 14 to find the quotient.
We see that 14 goes 5 times into 78 and leaves remainder of 8.
So we can rewrite 78/14 as .
means little more than 5 but less than 6.
So required two whole numbers are 5 and 6.