Sqrt(1-3x)=x+3
[sqrt(1-3x)]^2=(x+3)^2
1-3x=(x+3)(x+3)
1-3x=x^2+6x+9
-3x=x^2+6x+8
0=x^2+9x+8
The answers are -1 and -8 BUT, we have to plug them back into the original equation to make sure we don't get a negative under the square root sign.
After doing this, we realize that only -1 works, so the answer is x=-1
Sorry that this took forever to answer. I was thinking of a good way to explain this, and if you need any further explanation, message me:)
Best wishes:)
Answer:
It does
Step-by-step explanation:
It does have a proportional relationship because if you try to find the relationship between the first two inputs and outputs, you can find that it is 21 (1 to 21, 21 divided by 1 would be 21) then if you use that relationship with the other numbers (times 21) you would get the same answer. For example in the second one, the two numbers are 2 and 42, 2 times 21 would equal 42. The next one would be 3 times 21 to equal 63 and etc.
Hope this Helps!!
Step-by-step explanation:
Solve the system via elimination (add the equations):
-10y + 9x = -9
+ (10y + 5x = -5)
-----------------------
14x = -14
x = -1
Plug in the value for 'x' into the second equation:
-10y + 5(-1) = -5
Solve for y:
-10y - 5 = -5
--> -10y = 0
--> y = 0
x = -1
y = 0
