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Iteru [2.4K]
3 years ago
5

As a diameter of a circle increases the radius will

Mathematics
2 answers:
slega [8]3 years ago
5 0
The answer is true, im pretty sure
alekssr [168]3 years ago
5 0
Increase cause radius is half of diameter
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Stephen’s lunch bill is currently at $8.33. Stephen orders a fruit salad for take-out, and wants to leave $2.25 as a tip for his
KatRina [158]

Answer:

$4.42

Step-by-step explanation:

by combining $8.33 and $2.25 you get a combined total of $10.58 and if you subtract that from $15 you get $4.42 as the amount of money remaining.

7 0
3 years ago
I got the answer as letter C, can someone check me to make sure that is correct? Thank you in advance.
Flura [38]

Answer:

The x's cancel  so definitely is choice C:  1/9

Step-by-step explanation:

We have   root( 1/(x^2) )  *  root ((x^2) / 81)

simplifying this we get as follows:

root( 1/(x^2) )  *  root ((x^2) / 81)

= \sqrt{(1/x^2 )}  * \sqrt{(x^2)/81}

=  ( 1/x )   *  (x/9)

the x's cancel

= 1/9

choice C   1/9

3 0
3 years ago
Which number is the best estimate of 60,000,000,000?
Vedmedyk [2.9K]
The answer to your question is Total book value of debt = 60,000,000 + 35,000,000 = 95,000,000 Total market value of debt = 74,850,000 Book Value Market Price Market Value 60,000,000 95.00 57,000,000 35,000,000 51.00 17,850,000 74,850,000
8 0
10 months ago
Read 2 more answers
Please answer ASAP this has to be turned in soon.
Leni [432]

The answer is true, you have to follow PEMDAS


6 0
2 years ago
Read 2 more answers
Graph -x^2+x+6=0 and state the consecutive integers between which roots are located
KengaRu [80]

Answer:

The roots of given quadratic equation lies from \begin{bmatrix}-2 , 3 \end{bmatrix}

Step-by-step explanation:

Given as :

The quadratic equation is x² - x -6 = 0

The quadratic equation is in form of ax² + bx +c = 0

Let x1 and x2 be the roots of equation

Sum of roots

So, x1 + x2 = \frac{-b}{a}  

And products of roots is x1 × x2 = \frac{c}{a}

So, x1 + x2 = \frac{1}{1}  

Or,   x1 + x2 = 1          ......A

And  x1 × x2 = \frac{-6}{1}

Or,  x1 × x2 = - 6

Now, (x1 - x2)² = (x1 + x2)²+ 4×x1×x2

Or,  (x1 - x2)² = (1)²+ 4×6

Or,  (x1 - x2)² = 25

So , x1 - x2 = \sqrt{25} = 5          ......B

Now solve eq A and eq B

Or, (x1 + x2) + (x1 - x2) = 1 +5

Or, 2 x1 = 6

∴   x1 = 3     And     x2 = - 2

Hence The roots of given quadratic equation lies from \begin{bmatrix}-2 , 3 \end{bmatrix}   Answer

6 0
3 years ago
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