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Daniel [21]
3 years ago
5

Please answer all three.​

Mathematics
2 answers:
Harlamova29_29 [7]3 years ago
7 0

Answer:

1181.16

Step-by-step explanation:

Cylinder + Cube = 1181.16

sasho [114]3 years ago
4 0

Answer:

842.04 cm³

Step-by-step explanation:

Cylinder:

diameter = 6 cm

r = 6/2 = 3cm

h = 4 cm

Volume of cylinder = πr²h

                               = 3.14 * 3 * 3 * 4

                               = 113.04 cm³

Cube:

side = 9 cm

Volume of cube = side * side *side

                           = 9*9*9

                             = 729 cm³

Volume 0f composite figure = volume of cylinder + volume of cube

      = 113.04 + 729

      = 842.04 cm³

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3 years ago
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A set of exam scores is normally distributed and has a mean of 80.2 and a standard deviation of 11. What is the probability that
ZanzabumX [31]

Answer:

93.32% probability that a randomly selected score will be greater than 63.7.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 80.2, \sigma = 11

What is the probability that a randomly selected score will be greater than 63.7.

This is 1 subtracted by the pvalue of Z when X = 63.7. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{63.7 - 80.2}{11}

Z = -1.5

Z = -1.5 has a pvalue of 0.0668

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93.32% probability that a randomly selected score will be greater than 63.7.

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4 years ago
What is the fraction for five over two
nignag [31]

Answer:

So normally you would say it as

                  \       /

                <em>2 and 1/2</em>

                  /       \

<em>(2 1/2)</em>

<em></em>

*eliza*

<em></em>

<em></em>

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