Step-by-step explanation:
5x + 2 + 3x = 8x + 2
3 + 17x + 8 = 17x + 11
19 + 6x + 2x = 8x + 19
14x + 7 + 4 = 14x + 11
9x - 3 - 7x + 4 = 2x + 1
12x + 3x - 6 - 7f = 15x - 7f - 6
14x + 7 - 3x = 11x + 7
13z + 6u + 8x + 19 - u = 13z + 5u + 8x + 19
3z + 6 + 4z + 9 + 8u = 7z + 8u + 15
2x + 8z + 13u + 6z + 4u = 2x + 14z + 17u
14y + 13x + 12y + 19x + 4 = 26y + 32x + 4
5x + 18 - 13y + 12x + 8y = 17x - 5y + 18
21v + 8 - 12v - 7 + 3t - t = 9v + 2t + 1
3t + v - t + 7v = 2t + 8v
-1 + 18x -3y + x + 9y = 19x + 6y - 1
4x + 5y + 5x + 10y = 9x + 15y
With the curve

parameterized by

with

, and given the vector field

the work done by

on a particle moving on along

is given by the line integral

where

The integral is then


Answer: The system consists of parallel lines
Step-by-step explanation:
Given system of lines :

Substitute
in
, we get
, which is not true.
That means , system has no solution.
i.e. they are representing parallel lines. [Parallel lines do not intersect and hence they do not have solution.]
Answer:
we could migrate here
Step-by-step explanation:
In my work I used t=trains and m=minutes:
30+30= 60m/2t
<span>30+30= 60m/2t
</span><span>30+30= 60m/2t
</span><span>30+30= 60m/2t
</span><span>30+30= 60m/2t
</span><span>30+30= 60m/2t
</span><span>30+30= 60m/2t
</span><span>30+30= 60m/2t
</span><span>30+30= 60m/2t
</span><span>30+30= 60m/2t
</span><span>30+30= 60m/2t
</span><span>30+30= 60m/2t
Total= 720m/24t
1:30+1:30+1:30+1:30+1:30+1:30+1:30+1:30+1:30+1:30+1:30+1:30= 4 o' clock
Total= 372m/12t
24t+12t= 36t
The answer is:
36 trains in total</span>