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Svetlanka [38]
2 years ago
9

A frustum is formed when a plane parallel to a cone’s base cuts off the upper portion as shown.

Mathematics
2 answers:
aliya0001 [1]2 years ago
4 0
The volume of a cone is
V = (1/3) π r² h
where r =  radius of the base
h =  the height.

The volume of the frustum is
(1/3)π(7.5²)(11+8) - (1/3)π(3.5²)(8)
=(1/3)π(7.5²)(19) - (1/3)π(3.5²)(8)

The 3rd choice is the correct answer.

Answer:
\frac{1}{ 3}  \pi (7.5^{2})(19) -  \frac{1}{3}  \pi (3.5^{2})(8)


inn [45]2 years ago
3 0
Option c (choice 3) is the correct choice 
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77julia77 [94]

First, let's add all the x's.

x + x + x + x + x = 5x

5x - 1 + 1 + 1 + 1

Now, let's add together all the 1's that are being added (not the 1 that is being subtracted from 5x).


1 + 1 + 1 = 3

5x - 1 + 3

3 - 1 = 2

5x + 2

There's no way you can actually solve this unless you know the value of x; without x's value, this is as simplified as the expression is going to get.


Hope this helps!

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A coordinate plane from negative 8 to 8 along the x-axis and from negative 7 to 7 along the y-axis. Which steps should be used t
sdas [7]

Answer:

see the explanation

Step-by-step explanation:

we have

y-4=\frac{1}{3}(x+2)

This is the equation of a line in point slope form

where

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so

To graph the line

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What value does the 1 in the number 4,105.8
kirill115 [55]

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Step-by-step explanation:

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F(x)=x^2-2.g(x)=4x-2
Alex777 [14]

Answer:

Step-by-step explanation:

f(x) = x²-2

g(x) = 4x-2

f.g(x)= x²-2(4x-2) = x²(4x-2)-2(4x-2) = 4x³-2x²-8x+4

f.g(x) =  4x³-2x²-8x+4

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2 years ago
The distribution of weekly salaries at a large company is right skewed with a mean of $1000 and a standard deviation of $350. Wh
Shtirlitz [24]

Answer:

68.76% probability that the sampling error made in estimating the mean weekly salary for all employees of the company by the mean of a random sample of weekly salaries of 50 employees will be at most $50

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation, which is also called standard error s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 1000, \sigma = 350, n = 50, s = \frac{350}{\sqrt{50}} = 49.5

What is the probability that the sampling error made in estimating the mean weekly salary for all employees of the company by the mean of a random sample of weekly salaries of 50 employees will be at most $50

This is the pvalue of Z when X = 1000+50 = 1050 subtracted by the pvalue of Z when X = 1000-50 = 950. So

X = 1050

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{1050-1000}{49.5}

Z = 1.01

Z = 1.01 has a pvalue of 0.8438

X = 950

Z = \frac{X - \mu}{s}

Z = \frac{950-1000}{49.5}

Z = -1.01

Z = -1.01 has a pvalue of 0.1562

0.8438 - 0.1562 = 0.6876

68.76% probability that the sampling error made in estimating the mean weekly salary for all employees of the company by the mean of a random sample of weekly salaries of 50 employees will be at most $50

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