All categories

3 years ago

Find cos(2theta) if cos(theta)= 3/4

1 answer:

6 0

Sin theta = 8/17 and theta is in the second quadrant. Find sin(2theta),cos(2theta),tan(2theta) exactly sin(2theta) cos(2theta) tan(2theta) sin(2theta) would it be 2 x (8/17) cos(2theta) would be 2 x (15/17) tan(2theta) would be 2 x (8/17 divided by 15/17) is this correct?

You might be interested in

What is the circumference for a radius of 8mm

Anton [14]

Answer:

sixteen centimeter! hope this helps!

4 0

3 years ago

A piece of aluminum that is 20 cm³ has a mass of 54 g.<br> a. What is the density of the aluminum?

belka [17]

2.7 grams/ cm ³ , it will float

6 0

3 years ago

The volume of the sphere is 904.32 m. To the nearest meter, what is the radius of the sphere????? Use 3.14 for pi.

Rus_ich [418]

Answer:

Step-by-step explanation:

The formula for the volume of a sphere is $\frac{4}{3} \pi r^3$ . Plugging in the values that you are given, you get:

$904.32=\frac{4}{3}\pi r^3$

Dividing both sides by pi or 3.14:

$288=\frac{4}{3}r^3$

Dividing both sides by 4/3:

$216=r^3$

Taking the cube root of both sides:

$r=6$

Hope this helps!

8 0

3 years ago

Tomtit [17]

Answer:

hdbsushdjruejeuueusus

3 0

3 years ago

The box plots compare the number of calories in each snack pack of crackers and cookies.

Nikitich [7]

Answer:

4th statement is true.

Step-by-step explanation:

We have been two box plots, which represents the number of calories in each snack pack of crackers and cookies. We are asked to find the correct statement about our given box plots.

1. More packets of crackers have 80 calories than any other number of calories.

We can see that median of box plot representing calories of cookies is 80. This means that half of the packets of crackers have less than 80 calories and half of the packets have more than 80 calories, therefore, 1st statement is false.

2. The value 70 is an outlier for the number of calories in the cookie pack.

Since an outlier is 1.5 times the interquartile range.

$IQR=Q_3-Q_1$

$\text{IQR of cookie packs}=105-90$

$\text{IQR of cookie packs}=15$

$\text{Lower outlier}=Q_1-(1.5*IQR)$

$\text{Lower outlier}=90-(1.5*15)$

$\text{Lower outlier}=90-22.5$

$\text{Lower outlier}=67.5$

Since any number less than 67.5 will be an outlier and 70 is grater than 67.5, therefore, 70 is not an outlier in number of calories in cookie packs and 2nd statement is false.

3. The upper quartile of the cookie data is equivalent to the maximum in the cracker data.

We can see that upper quartile of cookie data is 105 and the maximum in cracker data is 100. Since 105 is greater than 100, therefore, 3rd statement is false.

4. The number of calories in each pack of cookies has a greater variation than the number of calories in each pack of crackers.

Since range and IQR are good measures of variation of box-plots, so we will find the range and IQR of our both box-plots.

We have already seen that IQR of cookie packs is 15.

$\text{IQR of cracker packs}=85-75$

$\text{IQR of cracker packs}=10$

$\text{Range}=\text{Maximum value - Minimum value}$

$\text{Range of calories in cracker packs}=100-70$

$\text{Range of calories in cracker packs}=30$

$\text{Range of calories in cookie packs}=115-70$

$\text{Range of calories in cookie packs}=45$

We can see that the range of calories in cookie packs (45) is greater than range of calories in cracker packs (30) and IQR of calories in cookie packs (15) is greater than IQR of calories in cracker packs (10), therefore, 4th statement is true.

3 0

4 years ago

Read 2 more answers