Answer:
it is expected that the mutation results in a reduced initiation of translation and thereby decreasing the level of the protein A, while it does not change the level of mRNA A
Explanation:
Translation in bacteria starts with the formation of the initiation complex which is composed of the small ribosomal subunit, the messenger RNA (mRNA), initiation factors and the initiator transference RNA (tRNA) containing N-formyl-methionine. The small ribosomal subunit binds to a polypurine stretch of variable length in the mRNA called 'the Shine-Dalgarno sequence'. A mutation in this sequence reduces the affinity of the ribosome for the mRNA, thereby, in this case, decreasing the level of protein A. Since transcription occurs before translation, it is expected that this mutation does not change the level of expression of the mRNA A.
Is this a question? True or false?
<span>Ni = 5
The Rydberg formula for hydrogen is
1/w = R(1/a^2 - 1/b^2)
where
w = wavelength in vacuum
R = Rydberg constant 1.0973731568508x10^7 1/m
a,b = integers greater than or equal to 1 and a < b
Now we need to select the value for a.
a = 1 will converge towards 91.13 nm
a = 2 converges towards 364.51 nm
a = 3 converges towards 820.14 nm
...
Because of this, we will assume a = 1 for this problem since it converges closest to the wavelength given.
Substitute known values
1/w = R(1/a^2 - 1/b^2)
1/9.504x10^-8 = 1.0973731568508x10^7(1/1^2 - 1/b^2)
10521885.52 = 1.0973731568508x10^7(1/1 - 1/b^2)
0.958824759 = 1 - 1/b^2
-0.041175241 = -1/b^2
0.041175241 = 1/b^2
24.28643927 = b^2
4.928127359 = b
So Ni = 5.</span>
Establish a hyperosmotic interstitial medullary concentration
