Let after t hours the distances D1<span> traveled by car A</span>
=> D1<span> = 30 t</span>
Car B starts at 10 am and will, therefore, have spent one hour less than car A when it passes it.
After (t - 1) hours, distance D2<span> traveled by car B </span>
=> D2<span> = 40 (t - 1)</span>
When car B passes car A, they are at the same distance from the starting point and therefore<span> D1 = D2 </span>
=> 30 t = 40 (t - 1)
Solve the equation for t,
=> 30 t = 40t - 40
=> 10 t = 40
=> t = 4
=><span> Car B passes car A at = 9 + 4 = 13 pm.</span>
180-65=115°
that's the answer
Given that:
- we cross multiply as follows:
- we divide both sides by G, as follows:
- Subtract 1 from both sides of the equation:
- multiply both sides of the equation by -1, as follows:
Therefore, we have that:
or:
