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Tanzania [10]
3 years ago
6

Which line shows the first error in the solution 6(x+2)=24

Mathematics
2 answers:
anzhelika [568]3 years ago
8 0
Line 4. 12 would be divided by 6, not multiplied. 
Ede4ka [16]3 years ago
6 0
The 4th line show the first error
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Please help I’ll give brainiest!<br><br> Make sure to tell me steps by steps!:D
asambeis [7]

Answer:

see below

Step-by-step explanation:

h(x) = 2x-10

Let x=3

h(3) = 2*3 -10

      = 6-10

      =4

Let x=-3

h(-3) = 2*-3 -10

      = -6-10

      =-16

6 0
3 years ago
Need urgent help doing this question!
xxMikexx [17]

⟘ = 90°

The intersect point is at the N not P, so the answer is m∠BNP = 90°

8 0
3 years ago
Which is equivalent to x(-14x + 9)?
victus00 [196]
SO YOU HAVE X(-14X+9). ALL YOU DO IS THE DISTRIBUTION PROPERY OR MULIPLE BY X

SO WE GET -14X^2+9X.

X(-14X+9)= -14X(*)X+9(*)X= -14X^2+9X

HOPE THIS HELPS
5 0
3 years ago
A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 201.9-cm and a standard dev
Nesterboy [21]

Answer:

There is a 0.08% probability that the average length of a randomly selected bundle of steel rods is greater than 204.1-cm.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 201.9-cm and a standard deviation of 2.1-cm. This means that \mu = 201.9, \sigma = 2.1.

For shipment, 9 steel rods are bundled together. Find the probability that the average length of a randomly selected bundle of steel rods is greater than 204.1-cm.

By the Central Limit Theorem, since we are using the mean of the sample, we have to use the standard deviation of the sample in the Z formula. That is:

s = \frac{\sigma}{\sqrt{n}} = \frac{2.1}{\sqrt{9}} = 0.7

This probability is 1 subtracted by the pvalue of Z when X = 204.1.

Z = \frac{X - \mu}{\sigma}

Z = \frac{204.1 - 201.9}{0.7}

Z = 3.14

Z = 3.14 has a pvalue of 0.9992. This means that there is a 1-0.9992 = 0.0008 = 0.08% probability that the average length of a randomly selected bundle of steel rods is greater than 204.1-cm.

3 0
3 years ago
What is the slope of the line passing through the points (0, −5) and (4, 2)?<br> __/__
Lorico [155]
Your slope is 7/4 

<span>https://gyazo.com/0aebab07f83794030e8fc922ac06610e
</span>
Proof in link
6 0
3 years ago
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