Question

3 people traveled 27 miles total and person number 2 went 6 miles more than person number 1 and person number 3 went 3 miles more than person number 2. Solve problem algebraically

Answer 1

Answer : The distance travelled by person 1, person 2 and person 3 is, 4 miles, 10 miles and 13 miles respectively.

Step-by-step explanation :

Let the distance travelled by person number 1 = x miles

Then, the distance travelled by person number 2 = (x+6) miles

And, the distance travelled by person number 3 = (x+6) + 3 miles = (x+9) miles

Total distance travelled by 3 persons = 27 miles

As per question,

x + (x+6) + (x+9) = 27

3x + 15 = 27

3x = 27 - 15

3x = 12

x = 4

The distance travelled by person number 1 = x miles = 4 miles

The distance travelled by person number 2 = (x+6) miles = (4+6) miles = 10 miles

The distance travelled by person number 3 = (x+9) miles = (4+9) miles = 13 miles

Answer 2

Answer:

3 miles,9 miles and 15 miles

Step-by-step explanation:

GIVEN: $3$ people traveled $27$ miles total and person number $2$ went $6$ miles more than person number $1$ and person number $3$ went $3$ miles more than person number $2$.

TO FIND: Solve problem algebraically.

SOLUTION:

Let the distance traveled by person $1$ be $x$

distance traveled by person $2$  $=x+6$

distance traveled by person $3=2x+9$

According to the question

Total distance traveled by all $=27$

$x+x+6+2x+9=27\implies4x+15=27$

$\implies 4x=12$

$\therefore x=3$

first person traveled $=3\text{ miles}$

Second person traveled $=x+6=9\text{ miles}$

Third person traveled $=2x+9=15\text{ miles}$

Hence person number 1,2 and 3 traveled 3 miles,9 miles and 15 miles respectively.