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Aleonysh [2.5K]
3 years ago
8

Y=X+1 is the equation for a straight line graph where does it cross the y-axis

Mathematics
1 answer:
ad-work [718]3 years ago
4 0
Y=x+1 crosses the y-axis at (0,1).  To solve this, I found out the y-intercept which is 1.  I know that the y-intercept is 1 because in the equation y=mx+b, the 'b' is the y-intercept.  The y-intercept is always on the y-axis and so this is where this equation crosses the y-axis.  

Below is a picture of the equation y=x+1 

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6. The sequence is recursive. Find the value of the next term in the sequence.
Alisiya [41]

Answer: the value is 30

Step-by-step explanation:

you are going up by 5 so 25+5 IS 30

CAN I HAVE BRAINLIEST PLEASE

8 0
3 years ago
State the gradient of the line perpendicular to the line y=3x-2
kherson [118]

Answer:

-1/3

Step-by-step explanation:

3 is the gradient of the other line

m1×m2=-1 (equation for perpendicular lines)

m1×3= -1

m1= -1/3

Pls confirm if its correct

correct me if wrong

thanks! :)

7 0
3 years ago
Maria and Nate graphed lines on a coordinate plane. Maria's line is represented by the equation y = -5/6x +8. Nate's line is per
eduard

Answer:

c)   6x - 5y = 15

Step-by-step explanation:

Slope-intercept form of a linear equation:  y=mx+b

(where m is the slope and b is the y-intercept)

Maria's line:  y=-\dfrac{5}{6}x+8

Therefore, the slope of Maria's line is -\frac{5}{6}

If two lines are perpendicular to each other, the product of their slopes will be -1.

Therefore, the slope of Nate's line (m) is:

\begin{aligned}\implies m \times -\dfrac{5}{6} &=-1\\m & =\dfrac{6}{5}\end{aligned}

Therefore, the linear equation of Nate's line is:

y=\dfrac{6}{5}x+b\quad\textsf{(where b is some constant)}

Rearranging this to standard form:

\implies y=\dfrac{6}{5}x+b

\implies 5y=6x+5b

\implies 6x-5y=-5b

Therefore, <u>option c</u> could be an equation for Nate's line.

3 0
2 years ago
I need help i dont know what to do
vladimir1956 [14]

9514 1404 393

Answer:

  ∠CAB = 28°

  ∠DAC = 64°

Step-by-step explanation:

What you do in each case is make use of the relationships you know about angles in a triangle and around parallel lines. You can also use the relationships you know about diagonals in a rectangle, and the triangles they create.

<u>Left</u>

Take advantage of the fact that ∆AEB is isosceles, so the angles at A and B in that triangle are the same. If we call that angle measure x, then we have the sum of angles in that triangle is ...

  x + x + ∠AEB = 180°

  2x = 180° -124° = 56°

  x = 28°

The measure of angle CAB is 28°.

__

<u>Right</u>

Sides AD and BC are parallel, so diagonal AC can be considered a transversal. The two angles we're concerned with are alternate interior angles, so are congruent.

  ∠BCA = ∠DAC = 64°

The measure of angle DAC is 64°.

(Another way to look at this is that triangles BCE and DAE are congruent isosceles triangles, so corresponding angles are congruent.)

8 0
3 years ago
In a triangle, the measure of the first angle is 24 degrees more than the measure of the second angle. The measure of the third
insens350 [35]

Answer:

104°

Step-by-step explanation:

let the second angle be x , then

the first angle is x + 24

the third angle is 4x , thus summing and equating to 180

x + x + 24 + 4x = 180, that is

6x + 24 = 180 ( subtract 24 from both sides )

6x = 156 ( divide both sides by 6 )

x = 26

Thus largest angle = 4x = 4 × 26 = 104°

6 0
3 years ago
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