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lidiya [134]
3 years ago
10

Write a 5 digitnumber that is divisible by 8?

Mathematics
2 answers:
ioda3 years ago
4 0
The largest 5-digit number divisible by 8 is 99992.
Eddi Din [679]3 years ago
4 0
Here are two options 99992 or 10000 are divisible by 8.
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In one city, taxi company A charges $5 plus $0.35/km travelled. Taxi company B charges $3.50 plus $0.50/km.
lions [1.4K]

Answer:

If you are asking for the equations, Company A would be 0.35x + 5 and Company B would be 0.50x + 3.50. :)

Step-by-step explanation:

3 0
2 years ago
Can somebody tell me which one it is? options are (BE, CF, DG, GF)
mixas84 [53]

Answer:

CF

Step-by-step explanation:

Mark as brainliest please

7 0
3 years ago
You have $12 to spend on pizza. It costs $9 plus $0.75 for each additional topping, tax included. Write and solve
nata0808 [166]

Answer:

9 + 0.75x =12     x=4

Step-by-step explanation:

7 0
3 years ago
For the given statement Pn, write the statements P1, Pk, and Pk+1.
Leno4ka [110]

Answer:

P_{1} =  2

P_{k} = k(k+1)

P_{k+1} = (k+1)(k+2)

Step-by-step explanation:

We are given the statement,

P_{n} as 2 + 4 + 6 + . . . + 2n = n(n+1)

That is,

P_{n} as 2 + 4 + 6 + . . . + 2n = \sum_{i=1}^{n}2i

So, we have,

P_{1} = \sum_{i=1}^{1}2i = 2

P_{k} = \sum_{i=1}^{k}2i = 2 + 4 + 6 + . . . + 2k = k(k+1)

P_{k+1} = \sum_{i=1}^{k}2i = 2 + 4 + 6 + . . . + 2k + 2(k+1) = (k+1)(k+2)

Thus, we get,

P_{1} =  2

P_{k} = k(k+1)

P_{k+1} = (k+1)(k+2)

7 0
3 years ago
Read 2 more answers
Find the value of x if -x+4=-9​
vladimir1956 [14]

Answer:

-13

Step-by-step explanation:

x+4=-9

  -4  -4

x= -13

If you did 9+4 you'd get 13. But instead its negative because x is negative.

6 0
3 years ago
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