can't simultaneously be equal to 1 and larger than 2, so the probability must be zero.
Did you mean to find the probability of the union? In that case, since the events are mutually exclusive, you would be able to write
where
is the probability density function and
is the cumulative distribution function for the random variable
.
x + y= 9 and x - y= 3
rearrange the second equation:
x - y= 3
x = 3 + y
x -3 = y
substitute y with "x-3" in the first equation and solve
x + y= 9
x + (x-3)= 9
2x -3 = 9
2x = 12
x = 6
you could also start with the first equation and substitute y in the second.
graphically speaking, it's the intersection point of to lines, at least the six-part of the point.
Answer:
Monday - First Graph
Wednesday - Third Graph on First Line
Friday - The third graph on 2nd Line
Step-by-step explanation:
This can be noticed by the variations in lines
Hope this helps
