Answer:
(a) P = 2x + 2r + 2πr
(b) x = ½(P - 2r - 2πr)
(c) x = 123 feet
Step-by-step explanation:
See Attachment for sketch of the track
Solving for (a): Perimeter of the track
This is calculated by adding the perimeter of the rectangle to the 2 semicircles as follows.
P = Perimeter of Rectangle + Perimeter of 2 Semicircles
P = 2(x + r) + 2 * πr
[Where r is the radius of both semicircles]
Open bracket
P = 2x + 2r + 2πr
Solving for (b): Formula for x
P = 2x + 2r + 2πr
Make x the subject of formula
2x = P - 2r - 2πr
Divide both sides by 2
x = ½(P - 2r - 2πr)
Solving for (c): the value of x when r = 50 and P = 660
Substitute the given values in the formula in (b) above
x = ½(P - 2r - 2πr)
x = ½(660 - 2 * 50 - 2π * 50)
x = ½(660 - 100 - 100π)
x = ½(560 - 100π)
Take π as 3.14
x = ½(560 - 100 * 3.14)
x = ½(560 - 314)
x = ½ * 246
x = 123 feet
Answer:
Undefined
Step-by-step explanation:
If the slope was a horizontal line, then we could say y=2, however, it is only going through the x-axis so it would be x=2, but in terms of y it is undefined.
The smallest possible value is 2625
Answer:
y = 4x - 7
Step-by-step explanation:
Slope = 4 ; x1 = 2 , y1 = 1
Slope point form: y -y1 = m(x -x1)
y - 1 = 4(x - 2)
y - 1 = 4x - 2*4
y -1 = 4x - 8
y = 4x - 8 +1
y = 4x - 7