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forsale [732]
3 years ago
8

FREE TEN POINTS TO WHOEVER ANSWERS RIGHT NOW!!!!!!!!!!!!!!!!!!!!!!Consider this equation:  2/3 x − 9 − 2x + 2 = 1 Which is an eq

uivalent equation after combining like terms? StartFraction 8 Over 3 EndFraction x minus 11 = 1 StartFraction negative 4 Over 3 EndFraction x minus 7 = 1 StartFraction 8 Over 3 EndFraction x minus 7 = 1 StartFraction negative 4 Over 3 EndFraction x minus 11 = 1
Mathematics
2 answers:
lana [24]3 years ago
7 0

Answer:

B. -4/3x-7=1

Step-by-step explanation:

marin [14]3 years ago
5 0

Answer:

(Option B) StartFraction negative 4 Over 3 EndFraction x minus 7 = 1  

Step-by-step explanation:

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Which of the values is equivalent to 5^–3? A) 1/15 B) 1/125 C) − 15 D) − 125
bazaltina [42]

Answer:

C 1/125

Step-by-step explanation:

5  ^−3

Calculate 5 to the power of −3 and get  

1/125

​

​

7 0
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A 30- foot tree broke from its base and fell against a house. If the tree touches the house at a height of 21 feet, how far is t
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balandron [24]
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5 0
3 years ago
Read 2 more answers
Match the equation with its graph. -2/3x - -1/4y=1/3
Volgvan
If the equation is -(2/3) x - (1/4) y = 1/3, it is a straight line, so you can use some special points to identify the graph.

It is easier is you solve the equation for y:

(1/4)y = - 1/3 - (2/3) x

y = (-4/3) - (8/3)x

That is the slope -y-intercept form of the equation.

That means that the slope is -8/3, and the y-intercept is -4/3.

Use this points to identify the graph:

x = 0 => y = - 4/3 ---> (0, - 4/3)

y = 0 => x = - 1/2 -----> (-1/2, 0)

Now you can punt those two points on the graph and draw the line that joins them.

With this procedure you can find the graph of any straight line.
4 0
3 years ago
Describe the end behavior of a ninth-degree polynomial with a negative leading coefficient
Degger [83]

Given:

The degree of polynomial = 9

Leading coefficient is negative.

To find:

The end behavior of the polynomial.

Solution:

Let the polynomial be P(x).

We have,

Degree of polynomial = 9, which is odd.

Leading coefficient is negative.

If the degree of a polynomial is odd and leading coefficient is negative, then

P(x)\to \infty\text{ as }x\to -\infty

P(x)\to -\infty\text{ as }x\to \infty

Therefore, the end behavior of the given polynomial is P(x)\to \infty\text{ as }x\to -\infty,P(x)\to -\infty\text{ as }x\to \infty.

5 0
3 years ago
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