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3 years ago

15

Find the equation of the line that passes through the point (−3, −4) and is parallel to the line that passes through the points

(−5, 1) and (7, −3). A) y = 1 3 x + 5 B) y = 3x − 5 C) y = −3x − 5 D) y = − 1 3 x − 5

1 answer:

Leni [432]3 years ago

3 0

Answer: the actual answer it d. y=-1/3x-5

Step-by-step explanation:

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If x is an odd number, write an expression for the odd number that directly follows x.

LenKa [72]

I believe the expression would be:

x+2

For example, if you have the odd number 3 as x, 3+2 would be 5, the next odd number.
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2 25/100

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2 1/4

Answer: 2 1/4

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Find the derivative of the inverse function of the original function f(x)=(x+1)^3-5

____ [38]

Answer:

Step-by-step explanation:

let f(x)=y

$y=(x+1)^{3} -5\\flip ~x~and~y\\x=(y+1)^{3}-5\\(y+1)^{3}=x+5\\y=(x+5)^{\frac{1}{3} } -1\\or~f^{-1}(x)=(x+5)^{\frac{1}{3} } -1\\(f^{-1})'(x)=\frac{1}{3} (x+5)^{\frac{-2}{3} }$

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3 years ago

Area triangles? it says show work so pls do

coldgirl [10]

$\large{\underline{\underline{\pmb{\sf {\color {blue}{Solution:}}}}}}$

Given,

Area = 225 yd²

Base = 30 yd

Height = [To be calculated]

To find:

The height of the given triangle.

We know that, area of a triangle is:

$\frac{1}{2} \times (b \times h) \\ \\ \leadsto \frac{1}{2} \times (30 \times h) \\ \\ \leadsto \frac{1}{2} \times 30h \\ \\ \leadsto \frac{1}{ \cancel{2}} \times \cancel{30}h \\ \\ \leadsto1 \times 15h \\ \\ \leadsto \: h = 15 \: yd$

Therefore, the require height is 15 yd.

$\green\star$ Proof:

$\frac{1}{2} \times (b \times h) \\ \\ \leadsto \frac{1}{2} \times (30 \times 15) \\ \\ \leadsto \frac{1}{ \cancel{2}} \times \cancel{450} \\ \\ \leadsto1 \times 225 \\ \\ area = 225 {yd}^{2}$

$\boxed{ \frak \red{brainlysamurai}}$

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2 years ago

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Wewaii [24]

12(3x+1<span>)

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3 years ago

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