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3 years ago

ITS URGENT!!PLEASE HELLPPPPPP!!!!!!! WHAT IS X

Mathematics

1 answer:

sergey [27]3 years ago

6 0

Answer:

x is a variable

Step-by-step explanation:

please mark me brainliest :p

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You are riding along a straight river from east to the west at speed of 160m/m. At a given time, you will see the bearing of a c

yuradex [85]

Using the given information, the width of the river is 505.96 m

<h3>Bearing and Distances</h3>

From the question, we are to determine the width of the river

Consider the given diagram,

Let F be the first position of the biker

S be the second position

and C be the position of the church

First, we will determine the distance covered from F to S

Speed = 160m/min

Time = 4 minutes

Using the formula,

Distance = Speed × Time

Distance covered = 160 × 4

Distance covered = 640 m

That is, /FS/ = 640 m

Now, consider ΔFSC

∠F = 90° - 70° = 20°

∠S = 90° + 56° = 146°

and ∠C = 180° - 20° - 146° = 14°

By the Law of Sines

$\frac{/FC/}{sin\ S}= \frac{/FS/}{sin\ C}$

∴ $\frac{/FC/}{sin\ 146^\circ}= \frac{640}{sin\ 14^\circ}$

$/FC/ =\frac{640 \times sin \ 146^\circ}{sin \ 14^\circ}$

/FC/ = 1479.33 m

Now,

By SOH CAH TOA

$cos \ 70^\circ = \frac{d}{/FC/}$

NOTE: d is the width of the river

∴ d = /FC/ × cos70°

d = 1479.33 × cos70°

d = 505.96 m

Hence, the width of the river is 505.96 m

Learn more on Bearing and distances here: brainly.com/question/19351991

#SPJ1

7 0

2 years ago

In a large school, it was found that 77% of students are taking a math class, 74% of student are taking an English class, and 70

Iteru [2.4K]

Answer:

0.81 = 81% probability that a randomly selected student is taking a math class or an English class.

0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class

Step-by-step explanation:

We solve this question working with the probabilities as Venn sets.

I am going to say that:

Event A: Taking a math class.

Event B: Taking an English class.

77% of students are taking a math class

This means that $P(A) = 0.77$

74% of student are taking an English class

This means that $P(B) = 0.74$

70% of students are taking both

This means that $P(A \cap B) = 0.7$

Find the probability that a randomly selected student is taking a math class or an English class.

This is $P(A \cup B)$ , which is given by:

$P(A \cup B) = P(A) + P(B) - P(A \cap B)$

$P(A \cup B) = 0.77 + 0.74 - 0.7 = 0.81$

0.81 = 81% probability that a randomly selected student is taking a math class or an English class.

Find the probability that a randomly selected student is taking neither a math class nor an English class.

This is

$1 - P(A \cup B) = 1 - 0.81 = 0.19$

0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class

6 0

3 years ago

Rebecca has 21 math problems to solve. She has solved 2-7 of them. How many problems has she solved

Blizzard [7]

She has solved 6 problems. 21/7 times 2 equals 6.

7 0

3 years ago

Can someone help me please and thank you ❤️

ASHA 777 [7]

Answer:

I think it would be C

He gor A because he thought that since there waz 3 containers that you would just add 2 because there was 3 containers.

7 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%5Cleft%28%5Csqrt%7B2%7D%2B1%5Cright%29%5Cleft%285%2B%5Csqrt%7B2%7D%5Cright%29" id="TexFormula

dsp73

<h3>Solution:</h3>

$( \sqrt{2} + 1)(5 + \sqrt{2}) \\ = \sqrt{2} (5 + \sqrt{2} ) + 1(5 + \sqrt{2} ) \\ = 5 \sqrt{2} + 2 + 5 + \sqrt{2} \\ = 7 + 6 \sqrt{2}$

<h3>Answer:</h3>

7 + 6√2

5 0

3 years ago

Read 2 more answers