Answer:
0.018 is the probability that a randomly selected adult has an IQ greater than 131.5
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 100
Standard Deviation, σ = 15
We are given that the distribution of IQ score is a bell shaped distribution that is a normal distribution.
Formula:
a) P(IQ greater than 131.5)
P(x > 131.5)
Calculation the value from standard normal z table, we have,
0.018 is the probability that a randomly selected adult has an IQ greater than 131.5