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2 years ago

Original price 9$ sale price 4$ what is the discount

Mathematics

1 answer:

EastWind [94]2 years ago

3 0

Answer:

about 55% off?

Step-by-step explanation:

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Six percent (6%) of all shoppers make an impulse purchase at the check-out counter in a grocery store. If a store has 650 custom

Nookie1986 [14]

Answer:

(e) 39

Step-by-step explanation:

The expected value (or the average number) of impulse purchases per day is given by the probability of an impulse purchase being made (6%) multiplied by the daily number of customers (650):

$E(X) =P(X)* n\\E(X) = 0.06*650\\E(X) = 39$

The average number of impulse purchases is 39 per day.

3 0

3 years ago

Model 3+ (-4) on the number line

Anon25 [30]

Answer:

-1

Step-by-step explanation:

If u add 3 whole numbers to a negative number 4 then it'll equal -1. Think of it like 4-3 but add the negative sign at the begining

3 0

2 years ago

Read 2 more answers

-13x=90-2y <br> -6x=48-2y

Kisachek [45]

While it's pretty obvious to most of us that

-13x=90-2y

-6x=48-2y

is a system of linear equations, it'd be well to include that info plus the instructions "solve this system of linear equations."

Subtract the 2nd equation from the first:

-13x=90-2y

+6x=-48+2y

-----------------------

-7x = 42. Then x = -42/7, or x = 6.

Now subst. 6 for x in either one of the given equations. Suppose we use the 2nd equation:

-6x=48-2y

Then -6(6)=48-2y, or -36 = 48 - 2y, or 2y = 48+ 36 = 84. Then y = 42.

The solution is (6, 42).

3 0

2 years ago

Assume that during each second, a job arrives at a webserver with probability 0.03. Use the Poisson distribution to estimate the

Savatey [412]

Answer:

The probability that at lest one job will be missed in 57 second is $=1- e^{-1.71}$ =0.819134

Step-by-step explanation:

Poisson distribution:

A discrete random variable X having the enumerable set {0,1,2,....} as the spectrum, is said to be Poisson distribution.

$P(X=x)=\frac{e^{-\lambda t}({-\lambda t})^x}{x!}$ for x=0,1,2...

λ is the average per unit time

Given that, a job arrives at a web server with the probability 0.03.

Here λ=0.03, t=57 second.

The probability that at lest one job will be missed in 57 second is

=P(X≥1)

=1- P(X<1)

=1- P(X=0)

$=1-\frac{e^{-1.71}(1.71)^0}{0!}$

$=1- e^{-1.71}$

=0.819134

6 0

3 years ago

Please help me with this problem <br> Evaluate (-½·3)³

-Dominant- [34]

Answer: -27/8

Step-by-step explanation:

$\left(-\frac{1}{2}\cdot \:3\right)^3$

$\mathrm{Apply\:exponent\:rule}:\quad \left(-a\right)^n=-a^n,\:\quad \mathrm{if\:}n\mathrm{\:is\:odd}$

$\left(-\frac{1}{2}\cdot \:3\right)^3=-\left(\frac{1}{2}\cdot \:3\right)^3$

$=-\left(\frac{1}{2}\cdot \:3\right)^3$

$\mathrm{Apply\:exponent\:rule}:\quad \left(a\cdot \:b\right)^n=a^nb^n$

$\left(\frac{1}{2}\cdot \:3\right)^3=\left(\frac{1}{2}\right)^3\cdot \:3^3$

$=-\left(\frac{1}{2}\right)^3\cdot \:3^3$

$=-\frac{1}{8}\cdot \:3^3$

$=-\frac{1}{8}\cdot \:27$

$=-\frac{27}{8}$

3 0

2 years ago