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Ilia_Sergeevich [38]

3 years ago

7

What is the equation of a circle with its center at (5,-2) and a radius of 3? A (x – 5)2 + (y + 2)2 = 3 B (x - 5)2 + (y + 2)2 =

9 C (x + 5)2 + (y – 2)2 = 3 D (x + 5)2 + (y - 2)2 = 9

1 answer:

lina2011 [118]3 years ago

4 0

Answer:

please forgive I want the points for my exam

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Please I need to get this done by tomorrow

Alenkinab [10]

Answer:

i think it is 8

4 0

3 years ago

Read 2 more answers

A square mosaic is made of small glass squares. If there are 256 small squares in the mosaic how many are along an edge?

Degger [83]

To do this, you got to square 256.

The square root of 256 is 16.

Therefore, there are 16 small squares on each edge of the mosaic.

Kinda proof:

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o o o o O
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25 squares. Square root is 5. 5 along each edge. My work shares same concept.

Extremely unnecessary proof:

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o   o   o   o   o   o   o   o   o   o   o   o   o   o   o   O
o   o   o   o   o   o   o   o   o   o   o   o   o   o   o   O
o   o   o   o   o   o   o   o   o   o   o   o   o   o   o   O
o   o   o   o   o   o   o   o   o   o   o   o   o   o   o   O
o   o   o   o   o   o   o   o   o   o   o   o   o   o   o   O
o   o   o   o   o   o   o   o   o   o   o   o   o   o   o   O
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o   o   o   o   o   o   o   o   o   o   o   o   o   o   o   O
o   o   o   o   o   o   o   o   o   o   o   o   o   o   o   O
o   o   o   o   o   o   o   o   o   o   o   o   o   o   o   O
o   o   o   o   o   o   o   o   o   o   o   o   o   o   o   O
o   o   o   o   o   o   o   o   o   o   o   o   o   o   o   O

There are 256 squares, and you can count 16 on each edge. this shows 16 times 16, or 16 squared, which is 256.

3 0

3 years ago

Read 2 more answers

Use Hooke's Law to determine the work done by the variable force in the spring problem. A force of 450 newtons stretches a sprin

vlada-n [284]

Answer:

The work done is 202.50Nm

Step-by-step explanation:

Given

$F =450N$

$x_1 = 30cm$

$x_2 = 60cm$

Required

The work done

First, we calculate the spring constant (k)

$F = kx_1$

$450N = k *30cm$

$k = \frac{450N}{30cm}$

$k =15N/cm$

So:

$F = kx_1$

$F(x) = 15x$

The work done using Hooke's law is:

$W =\int\limits^a_b {F(x)} \, dx$

This gives:

$W =\int\limits^{60}_{30} {15x} \, dx$

Rewrite as:

$W =15\int\limits^{60}_{30} {x} \, dx$

Integrate

$W =15 \frac{x^2}{2}|\limits^{60}_{30}$

This gives:

$W =15 *\frac{60^2 - 30^2}{2}$

$W =15 *\frac{2700}{2}$

$W =15 *1350$

$W =20250N-cm$

Convert to Nm

$W =\frac{20250Nm}{100}$

$W =202.50Nm$

7 0

3 years ago

A pole that is 3 m tall casts a shadow that is 1.74 m long at the same time a nearby building casts a shadow that is 50.75 m lon

bija089 [108]

87.5

Tall. /. Shadow
3 / 1.74=. X /. 50.75
Cross multiply
152.25= 3x
Divide by 3
X= 87.5

4 0

3 years ago

Match each circular flower bed on the left to its circumference and its area on the right. Some answer options on the right will

marin [14]

Answer:

Bed A --- Third Option

Bed B --- Fifth Option

Step-by-step explanation:

Flower Bed A)

The formula for circumference is:

$C=2\pi r$

The diameter of A is 10 feet. So, its radius is 5 feet.

Substitute 5 for r. So, the circumference of Bed A is:

$C=2\pi (5)=10\pi\text{ feet}$

The formula for the area of a circle is:

$A=\pi r^2$

Substitute 5 for r:

$A=\pi (5)^2$

Square and simplify:

$A=25\pi \text{ square feet}$

So, the circumference of Bed A is 10π feet and its area is 25π square feet.

Therefore, match Bed A to the third option.

Flower Bed B)

The radius of Bed B is 6 feet. Again, we can use the circumference and area formulas. Substitute 6 for r for circumference:

$C=2\pi (6)$

Multiply:

$C=12\pi\text{ feet}$

Substitute 6 for r for the area formula:

$A=\pi(6)^2$

Square and simplify:

$A=36\pi\text{ square feet}$

So, Bed B has a 12π feet circumference and a 36π square feet area.

Therefore, match Bed B to the fifth option.

And we're done!

8 0

3 years ago