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3 years ago

5 pens for 14 dollars rounded to the nearest hundred

Mathematics

1 answer:

tatiyna3 years ago

7 0

Answer:

Step-by-step explanation:

Your dumb

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HELP PLEASE I need help look below for the picture and please if you can explain your answer if not that’s fine but this is a bi

Olegator [25]

Answer:

y = (3/2)x - 3

Step-by-step explanation:

Slope-Intercept Form is: y = mx + b, where m is the slope and b is the y intercept.

The slope is (3-0)/(4-2) = 3/2

The y-intercept is shown in the graph to be (0,-3).

The equation is y = (3/2)x -3

3 0

3 years ago

Read 2 more answers

Find the slope of the line that passes through (10,8) and (8,0).

N76 [4]

Answer:

The slope of the line that passes through points ( -10, -8 ) and ( -8, -16 ) is -4.

Explanation:

Points given = ( -10, -8) and ( -8, -16)

Slope = ?

( -10, -8 ) : x1 = -10 and y1 = -8

( -8, -16 ) : x2 = -8 and y2 = -16

We know,

slope = y2 - y1 / x2 - x1

Slope = -16 - ( -8) / -8 - (-10)

slope = -16 + 8 / -8 + 10

slope = -8 / 2

slope = -4

Therefore, slope of the line that passes through points ( -10, -8 ) and ( -8, -16 ) is -4.

Step-by-step explanation:

3 0

3 years ago

On Monday, the ABC Company stock was at $12.80 per share. On Tuesday it gained $3.42, and then lost $9.70 on Wednesday. What is

solong [7]

Answer:

Step-by-step explanation:

12.80+3.42= 16.22

16.22-9.70= 6.52 that's your answer

6 0

3 years ago

Find the roots of h(t) = (139kt)^2 − 69t + 80

Sonbull [250]

Answer:

The positive value of $k$ will result in exactly one real root is approximately 0.028.

Step-by-step explanation:

Let $h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ , roots are those values of $t$ so that $h(t) = 0$ . That is:

$19321\cdot k^{2}\cdot t^{2}-69\cdot t + 80=0$ (1)

Roots are determined analytically by the Quadratic Formula:

$t = \frac{69\pm \sqrt{4761-6182720\cdot k^{2} }}{38642}$

$t = \frac{69}{38642} \pm \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$

The smaller root is $t = \frac{69}{38642} - \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ , and the larger root is $t = \frac{69}{38642} + \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ .

$h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ has one real root when $\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} = 0$ . Then, we solve the discriminant for $k$ :