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3 years ago

What are the steps you would take to find the difference of two decimals? Write three to four sentences.

Mathematics

2 answers:

lawyer [7]3 years ago

6 0

Write down the two numbers, one under the other, with the decimal points lined up.

Add zeros so the numbers have the same length.

Then subtract normally, remembering to put the decimal point in the answer.

Valentin [98]3 years ago

6 0

Answer:

The first step is to make the divisor a whole number by multiplying it by a power of 10. When you multiply the divisor by a power of 10, you must multiply the dividend by the same power of 10. Then divide. Check your answer using estimation.

Step-by-step explanation:

I did Edginuity

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Can someone help me out?

Bingel [31]

Answer: It would be C

Step-by-step explanation:

because on Sat. there were 80 discs and on Mon. there were 55 discs, so 55-80=25 and C is your answer

6 0

3 years ago

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This recipe makes 24 shortbread fingers.

Nutka1998 [239]

Answer:

40g butter

20g sugar

60g flour

Step-by-step explanation:

8 is 24/3

then divide all measured by 3

120/3 =40

60/3=20

180/3=60

3 0

3 years ago

Read 2 more answers

Factor Quadratics

iVinArrow [24]

Answer:

Step-by-step explanation:

x^2 - 6x - 27

(x - 9)(x+3)

7 0

3 years ago

The area of a rectangle is 300 square centimeters. If the sides of the rectangle are given as 5 centimeters and <img src="https:

joja [24]

<em>x</em> is 1000, and the other side of the rectangle is 60 cm.
Area is found by multiplying length by width. Using the sides we know we have
$300=5(\sqrt{x+2600})$
We divide both sides by 5:
$\frac{300}{5}=\frac{5\sqrt{x+2600}}{5}
\\
\\60=\sqrt{x+2600}$
To "undo" a square root, we square both sides:
$60^2=(\sqrt{x+2600})^2
\\
\\3600=x+2600$
Subtract 2600 from both sides:
3600-2600=x+2600-2600
1000=x
Now we substitute this into the side with x:
$\sqrt{x+2600}=\sqrt{1000+2600}=\sqrt{3600}=60$

3 0

3 years ago

The foci and the directrices of the hyperbola are labeled. Which equation represents the hyperbola? (x-3)^2/16 - y^2/9= 1 x^2/16

Gnom [1K]

Answer:

Step-by-step explanation:

Hyperbola are generally written as

(x-h)² / a² - (y-k)² / b² = 1

Where,

(h, k) is the center is

"a" is the semi-transverse axis

"b" is the semi-conjugate axis

The focus and the directives is generally describe as

The foci of the graph are

(h + a⋅e, k) and (h − a⋅e, k)

The directrices of the graph are

x = h + a / e and x = h − a / e

Comparing this to the equation given

1. (x-3)² / 4² - y² / 3² = 1

This is an hyperbole of centre (3,0)

And parallel to the x axis

2. x² / 4² - (y-3)² / 3² = 1

This is also an hyperbole of center (0,3) and parallel to the x axis

3. (y-3)² / 3² - x² / 4² = 1

This is an hyperbole parallel to the x axis

4. y² / 3² - (x-3)² / 1² = 1

This is an hyperbole parallel to the y-axis

5 0

3 years ago