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Sauron [17]
3 years ago
12

Find the midpoint of the line segment joining the points ​R(-3​,3​) and ​S(5​,6​).

Mathematics
1 answer:
miv72 [106K]3 years ago
4 0
Hey the answer is "The midpoint (x_m,y_m) of a line segment with endpoints (x_1,y_1) and (x_2,y_2) is the point with following coordinates (x_m,y_m)=((x_1+x_2)/2, (y_1+y_2)/2)"
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6 0
3 years ago
Write a set of data with six values that has a mean of 28, median of 29, and a range of 18
Basile [38]
Mean is average example
mean of x,y,z is (x+y+z)/3

so 6 values
mean of 28
that means that they add up to 168


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4 0
3 years ago
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Answer:

Step-by-step explanation:

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3 0
3 years ago
Anyone knowww? :) help!
Yuki888 [10]
The answer would be 17.
This is because, the format for finding out the hypotenuse of a triangle is--
a^2 + b^2 = c^2
So, it would translate to--
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8 0
3 years ago
Read 2 more answers
Find the perimeter of quadrilateral a(-5, 4), b(0, 3), c(4,-1), d(4,-5)
snow_lady [41]
Explanation:
Let us divide the quadrilateral formed by
A
(
6
,
5
)
,
B
(
2
,
−
4
)
,
C
(
−
5
,
2
)
and
D
(
−
3
,
6
)
in two parts,
Δ
A
B
C
and
Δ
A
C
D
.
Now let us find the lengths of their sides.
A
B
=
√
(
2
−
6
)
2
+
(
−
4
−
5
)
2
=
√
16
+
81
=
√
97
=
9.8489
B
C
=
√
(
−
5
−
2
)
2
+
(
2
+
4
)
2
=
√
49
+
36
=
√
85
=
9.2195
A
C
=
√
(
−
5
−
6
)
2
+
(
2
−
5
)
2
=
√
121
+
9
=
√
130
=
11.4018
Now as
s
1
=
1
2
(
9.8489
+
9.2195
+
11.4018
)
=
1
2
×
30.4702
=
15.2351
And area of
Δ
A
B
C
=
√
15.2351
(
15.2351
−
9.8489
)
(
15.2351
−
9.2195
)
(
15.2351
−
11.4018
)
=
√
15.2351
×
5.3862
×
6.0156
×
3.8333
=
√
1892.2545
=
43.5
A
D
=
√
(
−
3
−
6
)
2
+
(
6
−
5
)
2
=
√
81
+
1
=
√
82
=
9.0554
C
D
=
√
(
−
5
+
3
)
2
+
(
2
−
6
)
2
=
√
4
+
16
=
√
20
=
4.4721
s
2
=
1
2
(
9.0554
+
4.4721
+
11.4018
)
=
1
2
×
24.9293
=
12.4647
And area of
Δ
A
C
D
=
√
12.4647
(
12.4647
−
9.0554
)
(
12.4647
−
4.4721
)
(
12.4647
−
11.4018
)
=
√
12.4647
×
3.4093
×
7.9926
×
1.0636
=
√
361.2547
=
19.01
Hence area of quadrilateral
A
B
C
D
is
43.5
+
19.0
=
62.5
units.
4 0
3 years ago
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