Answer:
I will study about it and tell u
Answer:
I think I know the answer but not 100% sure
Step-by-step explanation:
Step 1: Complete the scatter plot
Step 2: After you get done, submit the answer and see what grade you get.
Here's our equation.

We want to find out when it returns to ground level (h = 0)
To find this out, we can plug in 0 and solve for t.


So the ball will return to the ground at the positive value of

seconds.
What about the vertex? Simple! Since all parabolas are symmetrical, we can just take the average between our two answers from above to find t at the vertex and then plug it in to find h!

Answer:
8400 cents
Step-by-step explanation:
SI=P×T×R
100
300×4×7
100
=$84
=8400 cents
D/-9<=-8 multiply both sides by -9
d,=72