D. [ctrl][end]
That should get you to the last cell in your worksheet.
[ctrl][home]
Will get you t<span>o quickly jump to the first cell in a worksheet.</span>
<span>C. Their monthly rent payment.</span>
The component of the database that prevents both students from getting the last seat is: transaction isolation
Data that enters the database are expected to maintain accuracy and also be consistent with the database structure.
So, when both students request for the last seat, the possibilities are:
- <em>Student A gets the seat</em>
- <em>Student B gets the seat</em>
The following is not a possibility
- <em>Both students get the seat</em>
- <em>None of the students gets the seat</em>
The above highlights means that, only one of the students would get the seat.
This is possible because of the concept called transaction isolation.
The transaction isolation ensures that the data requested by a user is <em>complete </em>and such data maintains <em>competency</em>.
So, when a student gets the last seat, the <em>next student </em>would not get the same seat (<em>or any other seat</em>), because a transaction has already been completed.
Read more about transaction isolation at:
brainly.com/question/13030145
Answer:
coupons = int(input("Enter the number of coupons you win: "))
candy_bars = int(coupons / 10)
gumballs = coupons % 10
print("Candy bars: " + str(candy_bars) + ", Gumballs: " + str(gumballs))
Explanation:
*The code is in Python.
Ask the user to enter the number of coupons
Calculate the number of candy bars, divide the coupons by 10 and typecst the result to int
Calculate the number of gumballs, use the modulo to find the remainder
Print the values
Answer:
The answer is 69.3 ms
Explanation:
if 1 MiB = 0.008388608 Gb
then 3 MiB = 3 x 0.008388608 = 0.025165824 Gb.
since the bandwidth is equally shared amongst two users, each user gets equal share of the bandwidth which is Total Bandwidth/Number of Users.(
The bandwidth for each user = 30.8/2 = 15.4 Gbps.
The time taken for the message to reach from host A to host B = 0.025165824/15.4 s = 0.00163414441 which is = 1.63 ms.
The link connection requires a setup time of 67.7 ms
Therefore, the net time required is = 67.7 ms +1.63 ms = 69.3 ms.
