In the U.S. a standard mortgage requires a down payment of

Create and test a user-defined function named ufnFullName that combines the values of the two parameters named FirstName and Las

8090 [49]

Answer:

public static String ufnFullName(String Fname, String Lname){

String FullName = Fname+" "+Lname;

return FullName;

}

Explanation:

Using Java programming language, the function is created to accept two String parameters (Fname and Lname)

These are concatenated into a new String FullName and returned by the function

See below a complete code that prompts users to enter value for first and last names then calls this method to display the full name

import java.util.Scanner;

public class FullName {

public static void main(String[] args) {

System.out.println("Enter First Name");

Scanner in = new Scanner(System.in);

String Fname = in.next();

System.out.println("Enter Last Name");

String Lname = in.next();

System.out.println("Your Full Name is "+ufnFullName(Fname,Lname));

}

public static String ufnFullName(String Fname, String Lname){

String FullName = Fname+" "+Lname;

return FullName;

}

}

8 0

3 years ago

A painting company has determined that for every 115 square feet or wall space, one gallon of paint and eight hours of labor wil

Kay [80]

The program to calculate the total paint cost and other values is given below.

#include <iostream>

using namespace std;

int main() {

int rooms, laborChrg = 18;

float paintChrg;

float feetPerRoom[rooms];

float paintReq, laborHrs, paintCost, laborCost, totalCost, totalsqft=0;

cout<<"Enter the number of rooms to be painted "<<endl;

cin>>rooms;

for(int i=0; i <= rooms; i++)

{

cout<<"Enter the square feet in room "<<endl;

cin>>feetPerRoom[i];

// shortcut operator which is equivalent to totalsqft = totalsqft + feetPerRoom[i];

totalsqft += feetPerRoom[i];

}

cout<<"Enter the cost of the paint per gallon "<<endl;

cin>>paintChrg;

laborHrs = (totalsqft/115)*8;

laborCost = laborHrs * laborChrg;

paintReq = totalsqft/115;

paintCost = paintReq * paintChrg;

totalCost = laborCost + paintCost;

cout<<"The number of gallons of paint required "<<paintReq<<endl;

cout<<"The hours of labor required "<<laborHrs<<endl;

cout<<"The cost of the paint is "<<paintCost<<endl;

cout<<"The labor charges are "<<laborHrs<<endl;

cout<<"The Total cost of the paint job is "<<totalCost<<endl;

return 0;

}

Explanation:

The header files for input and output are imported.

#include <iostream>

using namespace std;

All the variables are taken as float except labour charge per hour and number of rooms.

The user is asked to input the number of rooms to be painted. An array holds the square feet in each room to be painted.

cout<<"Enter the number of rooms to be painted "<<endl;

cin>>rooms;

for(int i=0; i <= rooms; i++)

{

cout<<"Enter the square feet in room "<<endl;

cin>>feetPerRoom[i];

totalsqft += feetPerRoom[i];

}

The above code asks for square feet in each room and calculates the total square feet to be painted simultaneously.

All the data to be displayed is calculated based on the values of labor charge per hour and gallons of paint needed, given in the question.

laborHrs = (totalsqft/115)*8;

laborCost = laborHrs * laborChrg;

paintReq = totalsqft/115;

paintCost = paintReq * paintChrg;

totalCost = laborCost + paintCost;

All the calculated values are displayed in the mentioned order.

7 0

4 years ago

Can you prove that the bleu areas are the same please?

Nookie1986 [14]

$\huge\color{darkred}{ \tt{NO!!}}$

8 0

2 years ago

Read 2 more answers

Sometimes, fourth-generation languages (4GLs) are called procedural languages

irakobra [83]

Hi!

In 1981, the term 4GL was actually used to refer to languages which were non-procedural. A procedural language does not possess object-oriented capabilities. 4GL's often times have OOP properties, so I believe the answer to this question is going to be false. =)

7 0

3 years ago

Given the list of customer segments below please create a new list of the names of the segments only using(a) a for loop(b) a li

Alchen [17]

Answer:

new_segment = [ ]

for segment in segments:

new_segment.append({'name': segment, 'average_spend': money})

print( new_segment)

Using list comprehension:

new_segment =[{'name': segment, 'average_spend': money} for segment in segments]

Using map():

def listing(a):

contain = {'name': segment, 'average_spend': money}

return contain

new_segment = [ ]

new_segment.append(map( listing, segment))

print(list(new_segment)

Explanation:

The python codes above create a list of dictionaries in all instances using for loop, for loop in list comprehension and the map function which collect two arguments .

7 0

3 years ago