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Tasya [4]
3 years ago
15

Hey guys please help ✋✋

Physics
1 answer:
Lemur [1.5K]3 years ago
6 0

Answer:

by using mearsung scale

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Which kind of friction requires more force to overcome rolling or sliding fricton?
ANTONII [103]
Sliding friction is harder to overcome, and steals
more energy whenever you're moving.

That's why we switched from sleds to wheels
several thousand years ago.
8 0
3 years ago
What happens when the object is placed at F? Explain<br> your answer.
34kurt

Answer:

Sample Response: No image will be formed because the rays will not converge to or diverge from a common point.

Explanation:

5 0
3 years ago
A Young'sdouble-slit interference experiment is performed with monochromatic light. The separation between the slits is 0.44 mm.
Artyom0805 [142]

Answer:

Explanation:

The double slit interference phonemene is described for the case of constructive interference

          d sin θ= m λ                   (1)

let's use trigonometry to find the sinus

        tan θ = y / L

in general in interference phenomena the angles are small

       tan θ = sin θ / cos θ = sin θ

 

The double slit interference phonemene is described for the case of constructive interference

          d sin θ = m lam                    (1)

let's use trigonometry to find the sinus

        tan θ = y / L

in general in interference phenomena the angles are small

       tan θ = sin θ / cos θ = sin θ

we substitute

      sin θ = y / L

we substitute in equation 1

         d y / L = m λ

         λ = dy / L m

let's reduce the magnitudes to the SI system

  d = 0.44 mm = 0.44 10⁻³ m

  y = 5.5 mm = 5.5 10⁻³ m

  L = 4.2m

  m = 1

let's calculate

        λ = 0.44  10⁻³ 5.5 10⁻³ / (4.2 1)

         

        λ = 5.76190 10-7 m

let's reduce to num

  lam = 5.56190 10-7 m (109 nm / 1m)

  lam = 556,190 nmtea

we substitute

      without tea = y / L

we substitute in equation 1

         d y / L = m lam

         lam = dy / L m

let's reduce the magnitudes to the SI system

  d = 0.44 me = 0.44 10-3 m

  y = 5.5 mm = 5.5 10-3

  L = 4.2m

  m = 1

let's calculate

        lam = 0.44 10⁻³  5.5 10⁻³ / (4.2 1)

         

        lam = 5.76190 10⁻⁷ m

let's reduce to num

  lam = 5.56190 10⁻⁷ m (109 nm / 1m)

  lam = 556,190 nm

6 0
4 years ago
25 Pts. - URGENT
Alex_Xolod [135]

Answer:

I'm pretty sure that it's -225, hope this helps

3 0
3 years ago
In a heat engine, Qh and Qc represents high temperature substance and low temperature substance respectively. Which of the follo
ElenaW [278]

The efficiency of a heat engine is given by the expression eff =\frac{Q_h-Q_c}{Q_h}

The efficiency of a heat engine is the ratio of the work done by the engine to the heat given as the input to the engine.

eff =\frac{W}{Q_h}

The heat engine absorbs Q h from the hot reservoir , performs a work <em>W</em> on the absorbed heat and rejects Qc to the cold reservoir.

Therefore, the work done  is given by,

W=Q_h - Q_c

Thus the efficiency is given by, eff =\frac{Q_h-Q_c}{Q_h}

6 0
3 years ago
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