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Sever21 [200]
3 years ago
13

You are choosing between two different cell phone plans. The first plan charges a rate of 24 cents per minute. The second plan c

harges a monthly fee of $34.95 plus 12 cents per minute.
Let
t
be the number of minutes you talk and
C
1
and
C
2
be the costs (in dollars) of the first and second plans. Give an equation for each in terms of t, and then find the number of talk minutes that would produce the same cost for both plans (Round your answer to one decimal place)
Mathematics
1 answer:
kupik [55]3 years ago
4 0

Answer:

C_{1}(t) = 0.24*t

C_{2}(t) = 34.95 + 0.12*t

291.25 talk minutes would produce the same cost for both plans.

Step-by-step explanation:

Both plans can be modeled by a first order equation in the following format:

C(t) = C_{0} + f*t

In which C_{0} is the initial cost, f is the fee that is paid for each minute, and t is the number of minutes.

Cost of the first plan:

The problem states that the first plan charges a rate of 24 cents per minute, which means that f = 0.24.There is no initial cost, so C_{0} = 0.

The equation for this plan is:

C_{1}(t) = 0.24*t

Cost of the second plan:

The problem states that the second plan charges a monthly fee of $34.95 plus 12 cents per minute. So C_{0} = 34.95 and f = 0.12

The equation for this plan is:

C_{2}(t) = 34.95 + 0.12*t

Find the number of talk minutes that would produce the same cost for both plan:

This is the instant t in which:

C_{1}(t) = C_{2}(t)

0.24t = 34.95 + 0.12t

0.12t = 34.95

t = \frac{34.95}{0.12}

t = 291.25

291.25 talk minutes would produce the same cost for both plans.

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3 years ago
If x is divided by 5 the remainder is 4. If why is divided by 5 the remainder is 1. What is the remainder when x+y is divided by
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Answer:

0

Step-by-step explanation:

We are given the following:

\frac{x}{5}=q_1+\frac{4}{5}      (equ. 1)

\frac{y}{5}=q_2+\frac{1}{5}      (equ. 2)

We are asked:

\frac{x+y}{5}=q_3+\frac{r}{5}  (equ. 3) , what is r?

The q_i's represent the quotients you get.

r is the remainder of dividing x+y by 5.

We know that r is a number in {0,1,2,3,4}.

x=5q_1+4 (I got this by multiplying both sides of equ 1. by 5.)

y=5q_2+1 (I got this by multiplying both sides of equ 2. by 5.)

Let's add these equations together:

x+y=(5q_1+5q_2)+(4+1)

Factoring the 5 out for the q_i's part and simplify 4+1 gives:

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So 5 can't be the remainder of dividing something by 5 but see that we can factor this right hand expression more as:

x+y=5(q_1+q_2+1)

So q_3=q_1+q_2+1 while there is no remainder (the remainder is 0).

Let's do an example if you are not convinced at this point that the remainder will be 0.

So choose x=9 since 9/5 gives a remainder of 4.

And choose y=16 since 16/5 gives a remainder of 1.

x+y=9+16=25 and 25/5 gives a remainder of 0.

8 0
3 years ago
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