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2 years ago

14

Please please help me with this question please now and show your steps

1 answer:

sattari [20]2 years ago

6 0

Answer:

$y = {x}^{2} - 8x + 7 \\ a = 1 \: and \: b = - 8 \\ the \: line \: of \: symmetry \: \\ x = \frac{ - b}{2a} = \frac{8}{2} \\ x = 4(line \: of \: symmetry) \\ y = {4}^{2} - 8(4) + 7 \\ = 16 + 32 + 7 = y = 55 \\ vertix \: is \: (4 ,55) \\ y = {0}^{2} - 8(0) + 7 \\ y = 7 \\ 0 = {x}^{2} - 8x + 7 \\ (x - 7)(x - 1) = 0$

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Select all statements below which are true for all invertible n×n matrices A and B

nirvana33 [79]

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</span>and
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3 years ago

Part ion even know of the hardest test

ladessa [460]

Given:

The equation of a line is:

$y=-\dfrac{5}{7}x+2$

A line passes through the point (-5,-3) and perpendicular to the given line.

To find:

The equation of the line.

Solution:

Slope intercept form of a line is:

$y=mx+b$ ...(i)

Where, m is the slope and b is the y-intercept.

We have,

$y=-\dfrac{5}{7}x+2$ ...(ii)

On comparing (i) and (ii), we get

$m=-\dfrac{5}{7}$

We know that the product of slopes of two perpendicular lines is always -1.

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$-\dfrac{5}{7}\times m_2=-1$

$m_2=\dfrac{7}{5}$

Slope of the required line is $\dfrac{7}{5}$ and it passes through the point (-5,-3). So, the equation of the line is:

$y-y_1=m_2(x-x_1)$

$y-(-3)=\dfrac{7}{5}(x-(-5))$

$y+3=\dfrac{7}{5}(x+5)$

Using distributive property, we get

$y+3=\dfrac{7}{5}(x)+\dfrac{7}{5}(5)$

$y+3=\dfrac{7}{5}x+7$

$y=\dfrac{7}{5}x+7-3$

$y=\dfrac{7}{5}x+4$

Therefore, the equation of the line is $y=\dfrac{7}{5}x+4$ . Hence, option A is correct.

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