Answer:
which question is it so I know which one to give you
Answer:
Step-by-step explanation:
The solution is the coordinates of the point where the lines intersect: (3,5)
Answer:
you cheater
Step-by-step explanation:
Tring to cheat because you don't feel like doing it. Hopefully you fail so you can learn your lesson
Answer:
The two horiz. tang. lines here are y = -3 and y = 192.
Step-by-step explanation:
Remember that the slope of a tangent line to the graph of a function is given by the derivative of that function. Thus, we find f '(x):
f '(x) = x^2 + 6x - 16. This is the formula for the slope. We set this = to 0 and determine for which x values the tangent line is horizontal:
f '(x) = x^2 + 6x - 16 = 0. Use the quadratic formula to determine the roots here: a = 1; b = 6 and c = -16: the discriminant is b^2-4ac, or 36-4(1)(-16), which has the value 100; thus, the roots are:
-6 plus or minus √100
x = ----------------------------------- = 2 and -8.
2
Evaluating y = x^3/3+3x^2-16x+9 at x = 2 results in y = -3. So one point of tangency is (2, -3). Remembering that the tangent lines in this problem are horizontal, we need only the y-coefficient of (2, -3) to represent this first tangent line: it is y = -3.
Similarly, find the y-coeff. of the other tangent line, which is tangent to the curve at x = -8. The value of x^3/3+3x^2-16x+9 at x = -8 is 192, and so the equation of the 2nd tangent line is y=192 (the slope is zero).
Answer: f(3) = 14
Concept:
Here, we need to understand the idea of evaluation.
When encountering questions that gave you an expression with variables, then stated: "If x = a, y = b, z = c" (a, b, c are all constants), this means you should substitute the value given for each variable back to the expression.
Solve:
<u>Given function</u>
f(x) = 4x + 2
<u>Substitute value of the x into the expression</u>
f(3) = 4(3) + 2
<u>Simplify by multiplication</u>
f(3) = 12 + 2
<u>Simplify by addition</u>
f(3) = 
Hope this helps!! :)
Please let me know if you have any questions
