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Elan Coil [88]
3 years ago
15

To study the effectiveness of a certain adult reading program, researchers will select a random sample of adults who are eligibl

e for the program. The selected adults will be given a pretest before beginning the program and a posttest after completing the program. The difference in the number of correct answers on the pretest and the number of correct answers on the posttest will be recorded for each adult in the sample. Which of the following is the most appropriate inference procedure for the researchers to use to analyze the results?a) A one-sample z-interval for a population proportion.b) A one-sample t-interval for a sample mean difference.c) A matched-pairs t-interval for a population mean difference.d) A matched-pairs t-interval for a sample mean difference.e) A two-sample t-interval for a difference between means.
Mathematics
1 answer:
navik [9.2K]3 years ago
6 0

Answer:

c) A matched-pairs t-interval for a population mean difference

Step-by-step explanation:

Matched-Pairs t-Test. A matched-pairs t-test is used to test whether there is a significant mean difference between two sets of paired data.

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A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as
Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let <em>X</em> = number of seconds in the batch.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.31.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

              =1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

                            ={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0
3 years ago
If f(1)=9 and f(n-1)+5 then find the value of f(6)
uysha [10]

Answer:

f-3+6

because f=9

Step-by-step explanation:

4 0
3 years ago
Two sporting goods stores are having discount sales on basketballs. • At one store, a basketball is on sale for 20% off the regu
arlik [135]

Answer:

$0.61

Step-by-step explanation:

1. Find the sales price of each store by multiplying the regular price by the % off to find the discount - then subtract.

    store A: 24.95*20% (or 0.20) = 4.99 (discount)

                   24.95 - 4.99 = 19.96 (sales price)

    store B: 25.80 * 25% (or 0.25) = 6.45 (discount)

                  25.80 - 6.45 = 19.35

To find the difference of sales price, subtract 19.96 - 19.35 = 0.61

5 0
4 years ago
1. It is a prime number larger than 20.​
Norma-Jean [14]

Answer:

23, 29, 31, 37, 41, 43, 47, 53, 59, 61

5 0
3 years ago
Read 2 more answers
A day in the month of January is randomly selected What is the probability of selecting a perfect square?
Stels [109]

Answer:

5/31

Step-by-step explanation:

there are 31 days in January 5 of those are prefect squares (1,4,9,16,25)

7 0
3 years ago
Read 2 more answers
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