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Elan Coil [88]
3 years ago
15

To study the effectiveness of a certain adult reading program, researchers will select a random sample of adults who are eligibl

e for the program. The selected adults will be given a pretest before beginning the program and a posttest after completing the program. The difference in the number of correct answers on the pretest and the number of correct answers on the posttest will be recorded for each adult in the sample. Which of the following is the most appropriate inference procedure for the researchers to use to analyze the results?a) A one-sample z-interval for a population proportion.b) A one-sample t-interval for a sample mean difference.c) A matched-pairs t-interval for a population mean difference.d) A matched-pairs t-interval for a sample mean difference.e) A two-sample t-interval for a difference between means.
Mathematics
1 answer:
navik [9.2K]3 years ago
6 0

Answer:

c) A matched-pairs t-interval for a population mean difference

Step-by-step explanation:

Matched-Pairs t-Test. A matched-pairs t-test is used to test whether there is a significant mean difference between two sets of paired data.

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CAN SOMEONE HELP ME PLS!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
tresset_1 [31]

Answer:

a. 81 feet

b. 1152 inches

c. 11 pounds

d. 1.5 gallons

6 0
3 years ago
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Vertices A and B of triangle ABC are on one bank of a river, and vertex C is on the opposite bank. The distance between A and B
Anna71 [15]

Answer:

The length of side b is 179 ft

Step-by-step explanation:

Given triangle ABC in which  

∠A = 33°, ∠B = 63°, c=200

we have to find the length of b

In ΔABC, by angle sum property of triangle

∠A+∠B+∠C=180°

33°+63°+∠C=180°

∠C=180°-33°-63°=84°

By sine law,

\frac{\sin \angle A}{a}=\frac{\sin \angle B}{b}=\frac{\sin \angle C}{c}

\frac{\sin \angle B}{b}=\frac{\sin \angle C}{c}

\frac{\sin 63^{\circ}}{b}=\frac{\sin 84^{\circ}}{200}

b=200\times \frac{\sin 63^{\circ}}{\sin 84^{\circ}}=179.182887\sim 179 ft

The length of side b is 179 ft

Option C is correct.

7 0
3 years ago
If measure FG = 120° and measure EH = 94, what is measure angle EPH?
tankabanditka [31]

Answer:

∠EPH = 107°

Step-by-step explanation:

∠EPH is an angle formed by two intersecting chords.

arc FG and arc EH are the arcs ∠EPH intercepts.

The relationship between an angle formed by intersecting chords and their intercepted arcs is that the angle is equal to half the sum of its intercepted arcs.

Which means that ∠EPH = 1/2 ( arc FG + arc EH )

If arc FG = 120° and arc EH = 94°

Then ∠EPH = 1/2 ( 120 + 94 )

120 + 94 = 214

214 / 2 = 107

Hence, ∠EPH = 107°

5 0
3 years ago
Read 2 more answers
In the equation y = X - 5, the y-intercept is
Semenov [28]
-5 is the intercept since y=mx+b, b being the intercept.
8 0
3 years ago
Read 2 more answers
PLEASE HELP
Tems11 [23]

QUESTION A

The given multiplication problem is

\frac{39}{64} \times \frac{8}{13}

Factor each term to obtain;

\frac{13\times 3}{8\times8} \times \frac{8}{13}

Cancel out the common factors to obtain;

\frac{1\times 3}{8\times1} \times \frac{1}{1}

Simplify to get;

\frac{3}{8}

QUESTION B

The given multiplication problem is

\frac{2}{3}\times \frac{1}{5}\times \frac{4}{7}

This the same as

\frac{2\times 1\times 4}{3\times 5\times 7}

This simplifies to;

\frac{8}{105}

QUESTION C

The given problem is

\frac{3}{5}\times \frac{10}{12} \times \frac{1}{2}

This is the same as

\frac{3}{5}\times \frac{5}{6} \times \frac{1}{2}

=\frac{1}{1}\times \frac{1}{2} \times \frac{1}{2}

This simplifies to

=\frac{1}{4}

QUESTION D.

The given expression is

\frac{4}{9}\times 54

Factor the 54 to obtain;

\frac{4}{9}\times 9\times 6

Cancel the common factors to get;

\frac{4}{1}\times 1\times 6

This simplifies to;

=24

QUESTION E

The given problem is

20\times 3\frac{1}{5}

Convert the mixed numbers to improper fraction to obtain;

=20\times \frac{16}{5}

=4\times5 \times \frac{16}{5}

Cancel the common factors to get;

=4\times1 \times \frac{16}{1}

=64

QUESTION F

The multiplication problem is

11 \times 2 \frac{7}{11}

Convert the mixed numbers to improper fractions to obtain;

11 \times \frac{29}{11}

Cancel out the common factors to get;

=1 \times \frac{29}{1}

Simplify;

=29

QUESTION G

The given problem is

5\frac{1}{3}\times 5\frac{1}{8}

Convert to improper fractions;

=\frac{16}{3}\times \frac{41}{8}

Cancel out the common factors to get;

=\frac{2}{3}\times \frac{41}{1}

=\frac{82}{3}

Convert back to mixed numbers

=27\frac{1}{3}

QUESTION H

The given expression is

10\frac{2}{3} \times 1\frac{3}{8}

Convert to improper fraction to get;

\frac{32}{3} \times \frac{11}{8}

Cancel common factors to get;

=\frac{4}{3} \times \frac{11}{1}

Simplify

=\frac{44}{3}

Convert back to mixed numbers;

=14\frac{2}{3}

7 0
3 years ago
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