Hello :
y= (-x-2)/(x+4)
clculate : x
y(x+4) = -x -2
yx +x = -2 - 4y
x(y+1) = - 2 -4y
x = (- 2 -4y )/(y+1)
so : g-1(x) = (-2-4x) / (x+1)
72 different orders, each soup can have a different meat and other* so take 4* 6* 3 because that is how many different combanations you can do
Answer:
On this case if we analyze the situation we see that we are analyzing a random variable related to the time.
And the time cannot be negative, and the standard deviation is almost equal to the mean, too large. So will not plausible to say that the random variable X would be distributed normal.
Step-by-step explanation:
The empirical rule, also known as three-sigma rule or 68-95-99.7 rule, "is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ)".
Let X the random variable who represent the courtship time (minutes).
From the problem we have the mean and the standard deviation for the random variable X.
So we can assume
On this case in order to check if the random variable X follows a normal distribution we can use the empirical rule that states the following:
- The probability of obtain values within one deviation from the mean is 0.68
- The probability of obtain values within two deviation's from the mean is 0.95
- The probability of obtain values within three deviation's from the mean is 0.997
So we need values such that
On this case if we analyze the situation we see that we are analyzing a random variable related to the time.
And the time cannot be negative, and the standard deviation is almost equal to the mean, too large. So will not plausible to say that the random variable X would be distributed normal.
Answer:
If a son were to have a grandchild, Bob and Fran would then have two great-grandchildren.
Step-by-step explanation:
C = children
G = grand children
GG = great grand children
Bob and Fran have 3 children, 2 sons(C) and 1 daughter(C).
Their 2 sons have 5 children(G) between them. One son has 2 children(G). Their daughter has 3 children(G) and 1 grandchild(GG).
If the son with 2 children had a grandchild(GG).
Now we can see that, at present we have a single great grand child that is of their daughter's.
As given, if a son were to have a grandchild, Bob and Fran would then have two great-grandchildren.
Answer:What was done from the first to the second equation was that the fraction was simplified. 126 and 32 have a common factors of 2.
126/32=(63*2)/(16*2)
The 2s in the top and bottom can cancel out, leaving the fraction 63/16.
In addition, since there are x terms on the top and bottom, they cancelled out as well.
x/x^3=1/x^2
This leaves an x^2 term on the bottom.
Thus, if a is 16, and b is 2, you will have an equivalent form of the fraction.
Step-by-step explanation: