Question

There are three consecutive even integers. half the sum of the second and third numbers is 65. what are the integers

Answer 1

3 consecutive even integers.....x, x + 2, and x + 4
1/2(x + 2 + x + 4) = 65....multiply both sides by 2, canceling out 1/2
x + 2 + x + 4 = 65 * 2
2x + 6 = 130
2x = 130 - 6
2x = 124
x = 124/2
x = 62

x + 2 = 62 + 2 = 64
x + 4 = 62 + 4 = 66

so ur numbers are : 62,64,66 <==