Answer:
The answer in the procedure
Step-by-step explanation:
Let
A1 ------> the area of the first square painting
A2 ----> the area of the second square painting
D -----> the difference of the areas
we have


case 1) The area of the second square painting is greater than the area of the first square painting
The difference of the area of the paintings is equal to subtract the area of the first square painting from the area of the second square painting
D=A2-A1


case 2) The area of the first square painting is greater than the area of the second square painting
The difference of the area of the paintings is equal to subtract the area of the second square painting from the area of the first square painting
D=A1-A2


Answer:
I'm sorry
Step-by-step explanation:
I don't know the answer
<h3>Given that it is arithmetic</h3>


Answer:
Answer is 81y^4z^4
Step-by-step explanation:
The expression is (-3yz) (-3yz) (-3yz) (-3yz).
Since all the four terms have power 1:
(-3yz)^1 (-3yz)^1 (-3yz)^1 (-3yz)^1
We know that we can add the powers if the terms have same base
So,
=(-3yz)^1+1+1+1
=(-3yz)^4
=(-3)^4(y)^4(z)^4.
If the power is an even number than the negative sign changes into positive sign.
=3^4y^4z^4
=81y^4z^4
Thus the answer is 81y^4z^4....