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musickatia [10]
3 years ago
7

Simplify negative 8 over 3 divided by negative 2 over 6

Mathematics
1 answer:
Art [367]3 years ago
5 0

Answer: The answer is 8

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What is the answer to this question below guys.
Mashutka [201]

Answer:

Step-by-step explanation:

6+8=14

7 0
3 years ago
3/30 = n/50<br><br> n = (Blank)<br><br> Find n.
lutik1710 [3]
The answer will be n=5

5 0
3 years ago
PLEASE HELP: Find the measure of the angle indicated. Arc BC is 80 degrees.
Marina CMI [18]
The angle is 80 degrees. The measure of an angle is the exact same as the angle measure of the included arc, so that makes angle BAC 80 degrees
7 0
3 years ago
D(x)=(x^2-12x+20)/(3x)
krok68 [10]

Answers:

Vertical asymptote: x = 0

Horizontal asymptote: None

Slant asymptote: (1/3)x - 4

<u>Explanation:</u>

d(x) = \frac{x^{2}-12x+20}{3x}

      = \frac{(x-2)(x - 10)}{3x}

Discontinuities: (terms that cancel out from numerator and denominator):

Nothing cancels so there are NO discontinuities.

Vertical asymptote (denominator cannot equal zero):

3x ≠ 0  

<u>÷3</u>   <u>÷3 </u>

x ≠ 0

So asymptote is to be drawn at x = 0

Horizontal asymptote (evaluate degree of numerator and denominator):

degree of numerator (2) > degree of denominator (1)

so there is NO horizontal asymptote but slant (oblique) must be calculated.

Slant (Oblique) Asymptote (divide numerator by denominator):

  •        <u>(1/3)x - 4    </u>
  •    3x)    x² - 12x + 20
  •             <u>x²        </u>
  •                  -12x
  •                  <u>-12x         </u>
  •                             20 (stop! because there is no "x")

So, slant asymptote is to be drawn at (1/3)x - 4



6 0
3 years ago
AC is included between ___________.<br><br> A. BC and AC<br> B. C. D. AB and BC
mojhsa [17]
<span>AC is included between <A and <C.</span>
3 0
3 years ago
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