I have no idea
But if you have her info, let her know how much she means to you and see if she can meet up with you or something
If you don’t have her info, try getting her number or social media from anyone else that might know
And I’d recommend waiting proposing to someone till after education/school (Depending on the age OfC).
But that’s totally up to you guys
And good luck btw!
82 is your answer , I subtracted 52-40 and got 12 , so I know that the RC side is 12 more than 70.
The surface area and the volume of the cone is 816.4 km² and 7536 km³ respectively.
<h3>What is volume?</h3>
Volume is the capacity of an object.
To calculate the surface area and volume of the cone shown above, we use equation 1 and equation 2 respectively.
Formula:
- S = πr√(r²+h²)............. Equation 1
- V = πr²h.................. Equation 2
Where:
- S = Surface area of the cone
- V = Volume of the cone
- r = Radius of the base of thye cone
- h = Vertical height of the cone.
From the diagram,
Given:
- r = 10 km
- h = 24 km
- π = 3.14
Substitute these values into equation 1 and equation 2 respectively.
- S = 3.14×10[√(24²+10²)
- S = 31.4(√676)
- S = 31.4×26
- S = 816.4 km²
Also for the volume of tyhe cone
- V = 3.14×10²×24
- V = 7536 km³
Hence, The surface area and the volume of the cone is 816.4 km² and 7536 km³ respectively.
Learn more about volume here: brainly.com/question/1972490
#SPJ1
Weight : Samples
<span>. . 10 . . : . 1000 </span>
<span>. . . W . . . : . . 10 </span>
<span>W/10 = 10/1000 </span>
<span>W = 100/1000 </span>
<span>[ x = 1/10 = 0.1 lbs ]</span>
Answer:
ΔGJH ≅ ΔEKF
HL: GH and EF
SAS: FK and JH (or GH and EF)
ASA: ∠JGH and ∠FEK (or ∠EFK and ∠JHG)
ΔGFJ ≅ ΔEKH
SSS: KH and FJ
SAS: ∠KEH and ∠FGJ
Step-by-step explanation:
List whatever angles/sides need to be congruent for the two triangles to be congruent.
Prove ΔGJH ≅ ΔEKF using....
- HL (Hypotenuse + Leg)
We already have two legs that are congruent (EK and GJ), so we just need the hypotenuses (GH and EF) to be equal.
- SAS (Side + Angle + Side)
1 pair of sides (EK and JG) are equal, and m∠EKF = m∠GJH. So we need one more side. You can either use FK and JH or GH and EF.
- ASA (Angle + Side + Angle)
1 pair of angles (∠EKF and ∠GJH) are already given as equal, and 1 pair of sides (EK and GJ) are equal. We just need one more pair of angles. So either ∠JGH and ∠FEK or ∠EFK and ∠JHG.
Prove ΔGFJ ≅ ΔEKH using...
- SSS (Side + Side + Side)
Two pairs of sides (EK + GJ and EH + FG) are equal, so KH and FJ need to be equal.
- SAS (Side + Angle + Side)
FG + EH and KE + GJ are equal. We need to use the angle in between them to use SAS, so ∠KEH and ∠FGJ need to be equal.