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kicyunya [14]
3 years ago
8

Given the following two points calculate the rate of change: (3,10) (7,10)

Mathematics
1 answer:
fomenos3 years ago
7 0

Answer:

The rate of change is zero

Step-by-step explanation:

When drawn on graph paper, the 2 points are horizontal (they have the same y-value). When plugging in values in the slope formula, (y2-y1)/(x2-x1) you will get 0/4, which is still zero.

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Does anyone know how to solve this?
Bezzdna [24]

Use this version of the Law of Cosines to find side b:

b^2 = a^2 + c^2 − 2ac cos(B)

We want side b.

b^2 = (41)^2 + (20)^2 - 2(41)(20)cos(36°)

After finding b, you can use the Law of Sines to find angles A and C or use other forms of the Law of Cosines to find angles A and C.

Try it....

6 0
3 years ago
IF you answer the question, Give me an explanation the question.
Art [367]

Answer:

2

Step-by-step explanation:

this is because the inequality sign says greater than OR equal too, this would make the line solid, and since it's greater, all the values above that line would be included in the inequality

3 0
3 years ago
What type of function is represented in the table of values shown below ?
Murljashka [212]
I’m going to go with Exponential
5 0
3 years ago
Which is the solution to (8.5 x 103)(2 x 105) expressed in scientific notation?
kenny6666 [7]

We have been given an expression (8.5\times 10^3)(2\times 10^5). We are asked to find the solution to our given expression expressed as scientific notation.

Let us simplify our given expression.

Using exponent property a^m\cdot a^n=a^{m+n}, we will get:

8.5\times 2\times 10^3\times 10^5

17\times 10^{3+5}

17\times 10^{8}

Now to write our answer in scientific notation, we need our 1st multiple between 1 and 10. So we will rewrite our expression as:

1.7\times 10\times 10^{8}

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Therefore, our required solution would be 1.7\times 10^{9}.

8 0
3 years ago
A line passes through (2, –1) and (8, 4). a. Write an equation for the line in point-slope form. b. Rewrite the equation in stan
pentagon [3]
The point-slope form of a line is:

y-y1=m(x-x1),  where m=slope and (x1,y1) is any point on the line

First we need to find the slope, which is (y2-y1)/(x2-x1)

m=(4--1)/(8-2)

m=5/6 and we can use either point, I'll use (8,4)

y-4=(5/6)(x-8)

That is your equation in point-slope form.

Now the standard equation of a line is ax+by=c

y-4=(5/6)(x-8)  we can perform the indicated multiplication on the right side

y-4=(5x-40)/6  multiply both sides by 6

6y-24=5x-40  add 24 to both sides

6y=5x-16  subtract 5x from both sides

-5x+6y=-16  and by convention, the standard equation of a line should be expressed with a positive coefficient for x, so multiply both sides by -1

5x-6y=16
8 0
3 years ago
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