$( \arcsin{x})'= \frac{1}{ \sqrt{1-x^2} } 
\\
\\ (\arcsin{(2x+1)})'= \frac{1}{ \sqrt{1-(2x+1)^2} } (2x+1)'= \frac{2}{ \sqrt{1-(4x^2+4x+1)} } =
\\
\\= \frac{2}{ \sqrt{-4x^2-4x} } =\frac{2}{ \sqrt{4x(-x-1} )} =\frac{2}{ 2\sqrt{x(-x-1} )} =\frac{1}{ \sqrt{x(-x-1} )}$

3 0

3 years ago

Mr. Jamison will stain the deck in his backyard, the deck has an area of 752.4 sqaure feet. If the deck is 33 feet long how wide

shtirl [24]

answer:The width of the deck is 22.8 feet.

Step-by-step explanation:

Since we have given that

Area of the deck = 752.4 square feet

Length of deck = 33 feet

Let width of deck be 'x'.

Since Deck is in the shape of rectangle.

As we know the formula for "Area of rectangle ":

\begin{gathered}Area=Length\times width\\\\752.4=33\times x\\\\\dfrac{752.4}{33}=x\\\\22.8=x\end{gathered}

Area=Length×width

752.4=33×x

752.4

22.8=x

Hence, the width of the deck is 22.8 feet.

6 0

3 years ago