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Alex17521 [72]
2 years ago
9

The cost of 10 balls is 280. Find the cost of 19 balls.​

Mathematics
2 answers:
PSYCHO15rus [73]2 years ago
8 0

Answer:

$532

Step-by-step explanation:

Hey There!

So to solve this problem the first thing that we want to do is find the cost of 1 ball

To do so we divide the total cost of 10 balls by 10

280/10=28 so each ball cost 28

now to find the cost of 19 balls we multiply the cost of 1 ball by 19

18x28=532

thus meaning 19 balls cost $532

s344n2d4d5 [400]2 years ago
6 0

Answer:

$532

Step-by-step explanation:

We need to find the cost of 1 ball and then multiply it by 19, here is the math:

280/10=28

Now we know that 28 is the cost of 1 ball.

28 x 19=532

The cost of 19 balls is $532

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Jorge bought 6 large balloons for a party. This was 25% of all the balloons he bought. How many total balloons did Jorge buy sho
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Answer:

The answer would be 24 balloons in total.

Step-by-step explanation:

Jorge bought 6 large balloons, which was 25% of ALL the balloons he bought.

Meaning that since 6 is 25% of the number 24, he bought 24 balloons in total.

PROOF:

25% * 24 = 6

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Step-by-step explanation:

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Polynomial Expression.

Step-by-step explanation:

8 0
2 years ago
The diagram shows a logo​
Charra [1.4K]

Answer/Step-by-step explanation:

✔️Find EC using Cosine Rule:

EC² = DC² + DE² - 2*DC*DE*cos(D)

EC² = 27² + 14² - 2*27*14*cos(32)

EC² = 925 - 756*cos(32)

EC² = 283.875639

EC = √283.875639

EC = 16.85 cm

✔️Find the area of ∆DCE:

Area = ½*14*27*sin(32)

Area of ∆DCE = 100.15 cm²

✔️Since ∆DCE and ∆ABE are congruent, therefore,

Area of ∆ABE = 100.15 cm²

✔️Find the area of the sector:

Area of sector = 105/360*π*16.85²

Area = 260.16 cm² (nearest tenth)

✔️Therefore,

Area of the logo = 100.15 + 100.15 + 260.16 = 460.46 ≈ 460 cm² (to 2 S.F)

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3 years ago
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