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tigry1 [53]
3 years ago
8

Can someone help me with this one?

Mathematics
1 answer:
Pavel [41]3 years ago
4 0

Answer:

21/25 = 84/100

17/20 = 85/100

21/25 < 17/20

Step-by-step explanation:

∵ The common multiple of 25 and 20 is 100

∵ 100 ÷ 25 = 4

∴ 21/25 = (21 × 4)/(25 × 4) = 84/100

∵ 100 ÷ 20 = 5

∴ 17/20 = (17 × 5)/(20 × 5) = 85/100

∵ 84 < 85

∴ 84/100 < 85/100

∴ 21/25 < 17/20

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i need help with number 7. its solving systems of equations by substitution. please show work!!! i need help
SIZIF [17.4K]
#7:
<span>Subtract </span>y<span> from both sides:
</span>-4x=6-y

Divide both sides by -4:

Answer:
x= -6-y/4


#7 part 2:

Add <span>y</span><span> to both sides:
</span>-5x=21+y

Divide both sides by -5:

Answer: x=-21+y/5

hope i helped!



7 0
3 years ago
I cant add mixed fractions with whole numbers
butalik [34]

If you add the whole number to the whole number part of the mixed number, and then add the fraction from the mixed number on to the end of that,  you get a new mixed number which is your answer.

3 0
3 years ago
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yKpoI14uk [10]

Answer:

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3 0
3 years ago
A rectangle is 12 feet long and 5 feet wide. If the length of the rectangle is increased by 25% and the width is decreased by 20
lisabon 2012 [21]

Answer:

30 square feet.

Step-by-step explanation:

We have to find the main area of the rectangle to determine the changes.

We know, Area of a rectangle = Length × Width

Given,

Length = 12 feet

Width = 5 feet

Therefore, the area of the rectangle = (12 × 5) Square feet.

The area of the rectangle = 60 square feet.

Now, if the length of the rectangle increased by 25%, the new length would be = 12 feet (12 feet × 25%) = 12 feet + 3 feet = 15 feet.

If the width increased by 20%, the latest width would be = 5 feet + (5 feet × 20%) = 5 feet + 1 foot = 6 feet.

The new area of that rectangle = (15 × 6) square feet = 90 square feet.

The changes of area from the previous rectangle is = (90 - 60) square feet = 30 square feet.

5 0
3 years ago
your grades on tests 1 2 and 4 are 82 76 and 90. unfortunately you cut the third test and received a 0. If you have one test lef
Dmitrij [34]

Answer:  No, he can't pass the course.

Explanation:

Since we have given that

Marks on tests 1, 2, and 4 are given by

82, 76, 90 respectively.

Unfortunately, he cut the third test and receive a 0.

According to question, we have given that passing grade for the course is 70, and his one test left to take ,

Let the marks obtained in fifth test be x

So,

\frac{82+76+90+0+x}{5}=70\\\\248+x=5\times 70=350\\\\x=350-248\\\\x=102

And it is not possible to get 102 over 100.

so, he can't still pass the course.

Hence, No, he can't pass the course.

8 0
3 years ago
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