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3 years ago

10

73 as a sum of distinct nonconcecutive numbers

1 answer:

nika2105 [10]3 years ago

7 0

Hey there,
since they are saying distinct nonconsecutive numbers
you can do really anything here to make as sum of 73
like 70+3=73
60+13=73
etc...
Not sure why a question like this is asked? Unless you made some mistake in posting the question? <span />

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Use set notation to write the members of the following set, or state that the set has no members. Odd numbers between 2 and 82 t

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Let the set of all Odd multiples of 9 between 2 and 82 be denoted by D, then, using set-builder notation,

$D=\{ 18n+9 \mid n \in \mathbb{N}, 0\le n\le 4 \}$

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Each member of the set is a term of the arithmetic progression

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Putting these facts together, we get the result

$D=\{ 18n+9 \mid n \in \mathbb{N}, 0\le n\le 4 \}$

Learn more about set-builder notation here: brainly.com/question/17238769

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